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3 years ago

Which statement is true

Mathematics

2 answers:

kykrilka [37]3 years ago

8 0

The second answer is the true statement

Svetach [21]3 years ago

3 0

The Second One Is True

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The diameter of a planet is about 10,652 mi. The diameter of the planet's moon is about 25% of the planet. What percent of the v

alekssr [168]

Answer:

$2\%$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> the scale factor

x----> the volume of the planet's moon

y---> the volume of the planet

$z^{3}=\frac{x}{y}$

In this problem we have

$z=0.25$

elevated to the cube

$z^{3}=0.25^{3}=0.015625$

Find the percent

$0.015625*100=1.56\%$

Round to the nearest whole number

$1.56\%=2\%$

5 0

3 years ago

Convert to scientific notation: 0.000000000003071=___x10^_

cestrela7 [59]

3.071 X10^12. if you move the decimal place to the right 12 times it will end up behind the 3.

8 0

3 years ago

There is 1/4 ounce of yeast in every 2 1/4 teaspoon of yeast. A recipe calls for 2 teaspoons of yeast. How many ounces of yeast

MrRissso [65]

1/4 ounce of yeast ... 2 1/4 teaspoons of yeast
x ounce of yeast = ? ... 2 teaspoons of yeast

If you would like to know how many ounces of yeast need to be in the recipe, you can calculate this using the following steps:

1/4 * 2 = x * 2 1/4
1/2 = x * 9/4 /*4/9
x = 1/2 * 4/9
x = 2/9

Result: 2/9 ounce of yeast needs to be in this recipe.

7 0

3 years ago

To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil

Fiesta28 [93]

Answer:

The sample has not met the required specification.

Step-by-step explanation:

As the average of the sample suggests that the true average penetration of the sample could be greater than the 50 mils established, we formulate our hypothesis as follow

$H_0$ : The true average penetration is 50 mils

$H_a$ : The true average penetration is > 50 mils

Since we are trying to see if the true average is greater than 50, this is a right-tailed test.

If the level of confidence is α = 0.05 then the $z_\alpha$ score against we are comparing with, is 1.64 (this is because the area under the normal curve N(0;1) to the right of 1.64 is 0.05)

The z-score associated with this test is

$z=\frac{\bar x-\mu}{s/\sqrt{n}}$

where

$\bar x$ = mean of the sample

$\mu$ = average established by the specification

s = standard deviation of the sample

n = size of the sample

Computing this value of z we get z = 3.42

Since z > $z_\alpha$ we can conclude that the sample has not met the required specification.

5 0

3 years ago

How do I show the workings out for subtraction 1.56 - 5.20 =

pogonyaev

The Soluton:

Given:

$1.56-5.20$

We are asked to evaluate the given expression.

Explanation:

Since the number you are taking away is greater than thenumber that you want to taake it away from, we have to swap the numbers and then the result will be a negative number.

Therefore, the correct answer is -3.64

6 0

8 months ago