Question

Hey!! can someone please help me with these math problems? I would appreciate it, thank you(:

Answer 1

{x=-1/3-10/3y

5x+20y=5

5(-1/3-10/3y)+20y=5

solve the equation

.

.

Y=5

substitute the value of y into the equation

x=-1/3-10/3×2

.solve the equation

.

.x=-7

(x,y)=(-7,2)

{3×(-7)+10×2=-1

5x(-7)+28×2=5

simplify

{-1=-1

5=5

the ordered pair is asolution

(X,Y)=(-7,2)

That's all!!!!

Answer 2

Answer:

x = -7 y = 2

Step-by-step explanation:

Let's solve this using the elimination method:

3x + 10y = -1. #1

5x + 20y = 5. #2

Multiply Eqtn #1 by -2

-6x - 20y = 2

5x + 20y = 5

Add these two equations together and we will get

-x = 7 or x = -7

Use this value of x into either Eqtn #1 or #2

3(-7) + 10y = -1 ----> 10y = 20 or y = 2