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3 years ago

Find the volume. Pls NO links

Mathematics

2 answers:

Vaselesa [24]3 years ago

6 0

Answer:

7*8*4/2

Step-by-step explanation:

112

White raven [17]3 years ago

3 0

Answer:

112 cm

Step-by-step explanation:

First find the area of the triangle. Formula: 1/2bh

Base of 8 times height of 4 = 32. Then you divide 32 by 2(or multiple by 1/2, it's essentially the same) to get 16.

Now that you've found the area of the triangle, you multiply that by the length of the shape. (7cm)

16*7 = 112

So the volume of the shape = 112cm^3

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Step-by-step explanation: 36/pi is 11.4591559 approximately it would be 11.5

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Answer:

100 wizards in magic club

Step-by-step explanation:

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3 years ago

Please help me- thank you

san4es73 [151]

Answer:
(2^2)(z^7)

Explanation:
The quotient rule states that if two powers have the same base and are on opposite places of a fraction (one is on the numerator, the other on the denominator), you subtract the exponents.

First looking at the powers with the bases of 2, 2^8 is the numerator and 2^6 is the denominator. When we subtract 8-6 we get 2, so 2^8/2^6 would simplify to 2^2.

Then, we look at the powers with the base of z. z^10 is the numerator and z^3 is the denominator. When we subtract 10-3 we get 7, so z^10/z^3 would simplify to z^7.

I hope this helps! Please comment if you have any questions:)

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4 years ago

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Why is the alamo important to us history?

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What is the area of ABC?

Salsk061 [2.6K]

Answer:

Area of triangle ABC = 10

Option C is correct.

Step-by-step explanation:

We need to find area of triangle ABC

We are given A(2,1) B(4,7) and C(6,3)

The formula used to find $Area \ of \ triangle=\frac{1}{2}base\times height$ ABC is:

In the given triangle base= AC and height = BC

First we need to find the distance between A and C and B and C

The formula used to find distance between AC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=2, y_1=1, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-2)^2+(3-1)^2}\\Distance=\sqrt{(4)^2+(2)^2}\\Distance=\sqrt{16+4}\\Distance=\sqrt{20}$

find distance between BC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=4, y_1=7, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-4)^2+(3-7)^2}\\Distance=\sqrt{(2)^2+(4)^2}\\Distance=\sqrt{4+16}\\Distance=\sqrt{20}$

So, We have height = $\sqrt{20}$ and base = $\sqrt{20}$

Finding area of triangle

$Area \ of \ triangle=\frac{1}{2}base\times height\\Area \ of \ triangle=\frac{1}{2}\sqrt{20} \times \sqrt{20} \\Area \ of \ triangle=\frac{1}{2}\times 20\\Area \ of \ triangle=10$

So, Area of triangle ABC = 10

Option C is correct.

7 0

3 years ago