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TEA [102]
3 years ago
13

Evaluate the expression for x = 3 y= 1/3 and z= 5. 12 x - 3y over 4 x - Z​

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

35.786

12(3) - 3(1/2)/4(3) - 5

This is then further simplified to:

36 - 1.5/7

And when you divide 1.5 by 7, the number (rounded) is .214.

Thus, subtract, and gain the final answer of 35.786.

Hope this helps!

Step-by-step explanation:

Can you please mark me brainliest

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After reading ¾ of a magazine on Sunday, 0.2 of the remainder on Monday, and 10 pages on Tuesday, Michael still had to read 42 p
icang [17]

Answer:

3 /4 of 2 is the answer to the question

3 0
3 years ago
Find the length of the side of rhoumbus whose diagonals are of length 6cm and 8cm.​
Artist 52 [7]

Answer:

In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -

one side of triangle =  6/2 =3 (half of the diagonal)

other side = 8/2 = 4

a^2 + b^2 = c2

3 ^2 + 4^2 = c^2

9+16 = c^2

c^2=25

c = \sqrt{25} = 5

the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !

6 0
3 years ago
Si f(x)=2x^{2}−3x+1 y g(x)=x−3. Entonces (f∘g)(−1) es:
WARRIOR [948]
Huh? this is very confusing 12
7 0
3 years ago
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0
3 years ago
3. In the figure below, find the values of x, y, and z.
Murrr4er [49]

Answer:

z= 13

x= 36

y= 18

Step-by-step explanation:

Solving for z.

We know that 108 degrees and (8z+4) are alternate exterior angles, so they are equal to each other.

We can set both of those angles equal to each other, and solve for our missing side, z.

108= 8z+4

104=8z

z= 13

Solving for x.

We know that 108 degrees and (3x) are alternate interior angles, so they would equal each other.

We can set both of these angles equal to each other, and solve for our missing side, x.

3x=108

x= 36

Solve for y.

We know that (4y) and (3x) are same side interior angles, so they would make 180 degrees. We know that (3x) would equal 108.

4y+108=180

4y= 72

y= 18

3 0
2 years ago
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