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gayaneshka [121]
3 years ago
11

I NEED HELP ASAP! ILL GIVE YOU 10 POINTS FOR THE RIGHT ANSWERS PLEASE!!!!!

Mathematics
1 answer:
djverab [1.8K]3 years ago
6 0
Part A:
f(x) = 20x
Part B:
6 gallons
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Each marble bag sold by Lucy's Marble Company contains 7 yellow marbles for every 5 green marbles. If a bag has 45 green marbles
Elan Coil [88]

Answer:

63 yellow marbles

Step-by-step explanation:

You can set up this equation as a proportion:

7/5 = x/45

Divide 45 by 5 to see what 7/5 must be multiplied by to get to x/45.

You should get 9, so also multiply 7 by 9 to get this:

7/5 = 63/45

This shows that there are 63 yellow marbles for 45 green marbles.

Please thank, rate, and mark brainliest! :)

5 0
3 years ago
Which numbers belong to the solution set of the inequality? check all that apply. x+10<50
Lelechka [254]

THE CORRECT SOLUTION WOULD BE THE LISTED LETTERS. B. , F.

4 0
3 years ago
What is the LCM of 12 46
STALIN [3.7K]

Answer:

To get the Least Common Multiple (LCM) of 12 and 46 we need to factor each value first and then we choose all the factors which appear in any column and multiply them:  

12:    

2

2

3

 

46:    

2

 

 

23

LCM:    

2

2

3

23

The Least Common Multiple (LCM) is:   2 x 2 x 3 x 23 = 276

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How do i put -8-3x=y in slope intercept form?
masha68 [24]
Slope intercept form : y = mx + b
<span>
-8-3x=y
</span>y = -3x - 8

Answer would the be : y = -3x - 8


6 0
3 years ago
You have a fishing line spool with an end that has an area of 20.0 cm2. how much fishing line do you need to wind around the spo
grandymaker [24]

Answer: 158.53 cm

Step-by-step explanation:

We know that the ends of a fishing line spool are circular in shape.

Given : The area of an end of fishing line spool = 20.0\cm^2   (1)

Area of a circle = \pi r^2                                (2)

Circumference of a circle = 2\pi r                           (3)

, where r is radius of the circle.

From (1) and (2), we have

\pi r^2=20\\\\\Rightarrow\ r^2=\dfrac{20}{\pi}\\\\\Rightarrow\ r=\sqrt{\dfrac{20}{\pi}}                

Circumference of fishing spool = 2\pi r               (using (3))

=2\pi \sqrt{\dfrac{20}{\pi}}=2\sqrt{20\pi}=2\times2\sqrt{5\pi}=4\sqrt{5\pi}

i.e. Fishing spool required to wind around the spool one time =4\sqrt{5\pi}\ cm

⇒ Fishing spool required to wind around the spool 10 times =10\times4\sqrt{5\pi}\ cm=40\sqrt{5\pi}\\\\=40\times\sqrt{5}\times \pi\\\\=40\times2.236\times\sqrt{3.14159}\\\\=89.44\times1.772453\\\\=158.528205473\approx158.53\ cm

Hence, you need 158.53 cm or about 159 cm of fishing line to wind around the spool 10 times.

7 0
3 years ago
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