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umka21 [38]
3 years ago
11

Y = 5x - 22 y = 4x - 17

Mathematics
2 answers:
Pie3 years ago
6 0
The answer is (5,3). You need to equal both sides out. So 5x-22=4x-17. That will give you x=5. After that you substitute 5 for x in one or both of the equations and get that y=3. Hope this helps!
alina1380 [7]3 years ago
4 0

Answer:

the answer is 2

Step-by-step explanation:

hope this helps

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Nitella [24]

Answer:

landing on a shaded portion and landing on an even number ; landing on a shaded portion and landing on a number greater than 3 ; landing on an unshaded portion and landing on an odd number ; and landing on an unshaded portion and landing on a number less than 2.

Explanation:

Mutually exclusive events are events that cannot occur at the same time.  Our spinner has two grey sections, on 1 and 3; and two white sections, on 2 and 4.

This means that the spinner cannot land on a shaded (grey) portion and land on an even number at the same time, since the grey sections are numbered 2 and 4, both of which are even numbers.

The spinner also cannot land on a shaded (grey) portion and land on a number greater than 3 at the same time; this is because the only number greater than 3 on the spinner is 4, which is a white portion.

The spinner cannot land on an unshaded (white) portion and land on an odd number, since the white sections are labeled 2 and 4, which are both even.

The only number on the spinner less than 2 is 1, which is grey; this means the spinner cannot land on a number less than 2 and an unshaded (white) portion at the same time.

5 0
4 years ago
Read 2 more answers
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The answers is 6= 9x+27
5 0
3 years ago
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qwelly [4]

Step-by-step explanation:

If PQRS is a quadrilateral inscribed in a circle, then the opposite angles of the quadrilateral are <u>supplementary</u><u>.</u>

y + 68° = 180° { being opposite angles of cyclic quadrilateral }

y = 180° - 68°

y = 112°

x + 82° = 180° { being opposite angles of cyclic quadrilateral }

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Hope it will help :)❤

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2 years ago
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Step-by-step explanation:

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3 0
2 years ago
Geometry help! Find part B
hram777 [196]

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I'm terribly sorry if it is wrong.

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