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allochka39001 [22]
3 years ago
6

Which two equations would be most appropriately solved by using the zero product property? Select each correct answer.

Mathematics
2 answers:
rusak2 [61]3 years ago
7 0

Anwser: 2x² + 6x = 0 and (x−3)(x+4)=0

LekaFEV [45]3 years ago
3 0
The zero product property tells us that if the product of two or more factors is zero, then each one of these factors CAN be zero.

For more context let's look at the first equation in the problem that we can apply this to: (x-3)(x+4)=0

Through zero property we know that the factor (x-3) can be equal to zero as well as (x+4). This is because, even if only one of them is zero, the product will immediately be zero.

The zero product property is best applied to factorable quadratic equations in this case.

Another factorable equation would be 2x^{2}+6x=0 since we can factor out 2x and end up with 2x(x+3)=0. Now we'll end up with two factors, 2x and (x+3), which we can apply the zero product property to.

The rest of the options are not factorable thus the zero product property won't apply to them.
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What is an equation of the line that passes through the point (-4,-3) and is perpendicular to the line 2x+3y=15
Katen [24]

Answer:

The equation would be y = 3/2x + 3

Step-by-step explanation:

First we have to find the slope of the original line. We can do this by solving for y.

2x + 3y = 15

3y = -2x + 15

y = -2/3x + 5

Now that we have the slope of -2/3, we know the slope of the new line will be 3/2. This is because perpendicular lines have opposite and reciprocal slopes. We can use that and a point in point-slope form to find the equation.

y - y1 = m(x - x1)

y + 3 = 3/2(x + 4)

y + 3 = 3/2x + 6

y = 3/2x + 3

5 0
3 years ago
What is the solution to the inequality |2n+5|>1?
Yuliya22 [10]
ANSWER

n <  - 3 \: or \: n>  - 2



EXPLANATION



The given inequality is,

|2n + 5|  \:  >  \: 1


By the definition of absolute value,



- (2n + 5)  \:  >  \: 1 \: or \: (2n + 5) \:  >  \: 1



We divide through by negative 1, in the first part of the inequality and reverse the sign to get,

2n + 5 \:   <   \:  - 1 \: or \: (2n + 5) \:  >  \: 1

We simplify now to get,

2n   \:   <   \:  - 1 - 5 \: or \: 2n  \:  >  \: 1 - 5


2n   \:   <   \:  - 6 \: or \: 2n  \:  >  \:  - 4


Divide through by 2 to obtain,

n   \:   <   \:  - 3 \: or \: n  \:  >  \:  - 2


4 0
3 years ago
Read 2 more answers
Solve 2x2 + 20x = −38. (1 point)
RoseWind [281]

Answer:

The solutions are x=-5+\sqrt{6}  and x=-5-\sqrt{6}


Step-by-step explanation:

we have

2x^{2} +20x=-38

Divide by 2 both sides

x^{2} +10x=-19 ------> x^{2} +10x+19=0

we know that


The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to


x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}


in this problem we have


x^{2} +10x+19=0

so


a=1\\b=10\\c=19


substitute

x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}


x=\frac{-10(+/-)\sqrt{100-76}}{2}


x=\frac{-10(+/-)\sqrt{24}}{2}


x=\frac{-10(+/-)2\sqrt{6}}{2}


x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}


x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}


8 0
3 years ago
Read 2 more answers
Z=5x-11y ?<br><br> and-2-5v &lt; 8
velikii [3]

Answer:

Step-by-step explanation: v> -2 the > has a line under it

3 0
3 years ago
Solve the system by finding the determinants and using Cramer's Rule:<br> 2x - y = 4<br> 3x + y = 1
Ahat [919]

Answer:

<em>(1, - 2) </em>

Step-by-step explanation:

2x - y = 4

3x + y = 1

A = \left[\begin{array}{cc}2&-1\\3&1\end{array}\right] = 2(1) - 3( - 1) =2 + 3 = 5

A_{x} = \left[\begin{array}{cc}4&-1\\1&1\end{array}\right] = 4(1) - 1(- 1) = 4 + 1 = 5

A_{y} = \left[\begin{array}{cc}2&4\\3&1\end{array}\right] = 2(1) - 4(3) = 2 - 12 = - 10

<em>x </em>= \frac{A_{x} }{A} =<em> 1</em>

<em>y </em>= \frac{A_{y} }{A} = <em>- 2</em>

<em>(1, - 2)</em>

5 0
2 years ago
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