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3 years ago

What direction and what type of dot would you graph the inequality x > -9?

Mathematics

1 answer:

marishachu [46]3 years ago

7 0

Answer:

B. Open to the right

Step-by-step explanation:

X cannot be -9 so the dot has to be open

X is greater than -9 so x can be anywhere from -8 to 1,999,999,999 or even greater

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How do i solve this help me

Dmitriy789 [7]

Answer:

-24

Step-by-step explanation:

First substitute

(6x8)/-2

Then solve

48/-2=-24

-24

6 0

3 years ago

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There are five marbles in a bag. Three are green and two are yellow. You draw a marble, replace it and then draw another. What i

horsena [70]

2 to 5 or 2:5
or
2 to 3 or 2:3

6 0

4 years ago

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Sum of 1/2*3 +1/3*4 +1/4*5 ..1/99*100

geniusboy [140]

Answer:

11∗2+13∗4+15∗6+⋯+199∗100=?

=(1−12)+(13−14)+(15−16)+⋯+(199−1100)

=(1+13+15+17+⋯+199)−(12+14+16+⋯+1100)

=(1+13+15+17+⋯+199)−12(1+12+13+⋯+150)

=∑k=15012k−1−∑k=15012k

Continue further.

4 0

2 years ago

Will give brainliest, thanks, and 5 stars! LOTS OF POINTS! 50 POINTS!

lubasha [3.4K]

Answer in order:

False

True

False

True

Step-by-step explanation:

All of the solutions to the equation $3x^2 - 12 = 0$ are x = 12 and x = -12

Solve:

Common factor - $3(x^2-4)=0$

Divide both sides

$x^2-4=0$

Use the quadratic formula

$x=\sqrt{4,x}=\sqrt{-4$

x = 2, x = -2

Thus, This is false..

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There are two unique solutions to the equations (x-3)^2 = 16

one variable in matrix = one possible value.

Therefore, x = 7, x = -1

Hence this is True

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The solutions for the equation 2(x-3)^2-18 = 0 are x = 6 and x = 0

$2x^3-18x^2+54x-72=0$

$x=5.080084$

Hence this is false

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The solutions for the equation 2(x-5)^2-8=0 are x = 7 and x = -7

Add both sides by 8

2(x-5)^2-8+8=0+8

2(x-5)^2=8

(x-5)^2=4

x = 7, x = 3

Hence, this is false

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The solutions for the equation (x + 3)^2-25 = -8 are x = 2 and x = -8

$(x+3)^2=17$

$x=\sqrt{17-3,}=-\sqrt{17}-3$

Hence this is false.

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The solutions for the equation 2(2x-1)^2=18 are x = 5 and x = -4

$(2x-1)^2=9$

x=2, x = -1

Hence this is false.

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The only solution for equation (2x-1)^2-49=0 is x = 4

$(2x-1)^2=49$

x = 4, x = -3

Hence, this is false

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The solutions for the equation 3(x+2)^2 - 3 = 0 are x = -3 and x = -1

$3(x+2)^2=3$

$(x+2)^2=1$

x = -1, x = -3

Hence, this is true

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The solutions for the equation 5x^2 - 180 = 0 are x = 6 and x = -6

Add 180 to both sides

$5x^2-180+180=0+180$

$5x^2 = 180$

$x^2 = 36$

$x=\sqrt{36},x=-\sqrt{36}$

x = 6, x = -6

Hence, this is true.

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[RevyBreeze]

7 0

3 years ago

How many numbers less than 51 are a product of two different prime numbers?

NeTakaya

3x17= 51 is the answer

4 0

2 years ago

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