Answer:
a) Sample correlation coefficient, r = 0.7411
bi) test statistic, t = 4.102
bii) P-value = 0.000736
Step-by-step explanation:
a) The formula for the sample correlation coefficient is given by the formula:



r = 0.7511
b)
i) formula for the test statistic is given by the formula:

sample size, n = 4

t = 4.102
ii) Degree of freedom, df = n -2
df = 14 -2
df = 12
The P-value is calculate from the degree of freedom and the test statistic using excel
P-value =(=TDIST(t,df,tail))
P-value = (=TDIST(4.1,12,1)
P-value = 0.000736
So, values of x are: 
Step-by-step explanation:
We need to find the square root of 5x^2 = 300
Writing in mathematical form:

Divide both sides by 5


Taking square root on both sides






So, values of x are: 
Keywords: Square root
Learn more about square root at:
#learnwithBrainly
Answer:
Well, I think that the 50% coupons would give you only 50% off of your entire purchace. Not 100% off.
Step-by-step explanation: