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3 years ago

Ten times the smallest of three consecutive integers is 213 more than the sum of the other two integers. Find the integers.

Mathematics

1 answer:

mihalych1998 [28]3 years ago

4 0

Answer:

27,28 and 29

Step-by-step explanation:

10*a = a+1+a+2+213

10a - 2a = 216

8a = 216

a = 27

27, 28, and 29

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What is √-11 in the form a+bi?

Mice21 [21]

Given:

The number is $\sqrt{-11}$ .

To find:

The a+bi form of given number.

Solution:

We have,

$\sqrt{-11}$

It can be written as

$\sqrt{-11}=\sqrt{-1\times 11}$

$\sqrt{-11}=\sqrt{-1}\times \sqrt{11}$ $[\because \sqrt{ab}=\sqrt{a}\sqrt{b}]$

$\sqrt{-11}=i\times \sqrt{11}$ $[\because \sqrt{-1}=i]$

$\sqrt{-11}=\sqrt{11}i$

Here, real part is missing. So, it can be taken as 0.

$\sqrt{-11}=0+\sqrt{11}i$

So, a = 0 and $b=\sqrt{11}$ .

Therefore, the a+bi form of given number is $0+\sqrt{11}i$ .

5 0

3 years ago

Please answer this as soon as possible.

Vlad [161]

I’m pretty sure it’s b

7 0

3 years ago

Secants ⎯⎯⎯⎯⎯⎯⎯⎯ and ⎯⎯⎯⎯⎯⎯⎯⎯⎯ intersect in the exterior of a circle. The measures of ⏜ and ⏜ are 112.54° and 26.32°, respective

Veseljchak [2.6K]

Answer:

C. 43.11°

Step-by-step explanation:

The formula to use in finding m<BCD = ½ the difference of the intercepted arcs AE and BD

Thus:

m<BCD = ½(AE - BD)

m<BCD = ½(112.54 - 26.32)

m<BCD = ½(86.22)

m<BCD = 43.11°

5 0

3 years ago

if you had a cube with a side length of 4, how can you write the calculations in exponential form? what are 2 other ways to read

lesya692 [45]

4^3
You Would Write Is 4x4x4
You Would Verbally Say Four To The Third Or Four Cubed

5 0

3 years ago

A 2?-ft wide circular track for a camera dolly is set up for a movie scene. The two rails of the track form concentric circles.

navik [9.2K]

Answer: A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.

Step-by-step explanation:

Since we have given that

Radius of inner circle = 57 ft

As we know the formula for "Circumference of circle":

$Distance=Circumference=2\pi r\\\\Distance=2\times \frac{22}{7}\times 57\\\\Distance=358.28\ Ft$

Since we have also mentioned that there is 2 feet wide circular track for a camera dolly.

So, Radius of outer circle will be given as

$57+2\\=59\ ft$

So, Distance = Circumference is given by

$Distance=2\pi R\\\\Distance=2\times \frac{22}{7}\times 59\\\\Distance=370.85\ ft$

Hence, Difference between the outer rail travel than a wheel on the inner rail travel is given by

$370.85-358.28\\\\=12.57\ ft$

Therefore, A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.

7 0

3 years ago