Ten times the smallest of three consecutive integers is 213 more than the sum of the other two integers. Find the integers.

Mathematics

1 answer:

mihalych1998 [28]2 years ago

4 0

Answer:

27,28 and 29

Step-by-step explanation:

10*a = a+1+a+2+213

10a - 2a = 216

8a = 216

a = 27

27, 28, and 29

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