Ten times the smallest of three consecutive integers is 213 more than the sum of the other two integers. Find the integers.
1 answer:
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Answer: 1440
Step-by-step explanation:
To arrange 3 boys and 4 girls such that no two boys are together.
Since boys should be arranged between the girls.
So first arrange the girls.
Assume that the girls are placed, then there will be 5 spaces left for 3 boys.
The number of combinations to fill these places =
Also, 3 boys can arrange themselves in 3! =3 x 2 x 1 = 6 ways
4 girls can arrange themselves in 4! = 4x 3 x 2 x 1 = 24 ways
Then, the total number of arrangements = 10 x 6 x 24 = 1440
Hence, the required number of arrangements = 1440
Answer: a = -2/3
Step-by-step explanation:
Let's start by multiplying both sides by to simplify:
Looking only at the exponents, it seems like , so
.