Ten times the smallest of three consecutive integers is 213 more than the sum of the other two integers. Find the integers.
1 answer:
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Answer:
Number of large boxes: 55
Number of small boxes:65
Step-by-step explanation:
Let be "l" the number of large boxes and "s" the number of small boxes.
Set up a system of equations:
Use the methof of elimination. Mulitply the first equation by -60 and add both equations. Then solve for "s":
Substitute s=65 into any of the original equations and solve for "l":