Always younger than the rock it intrudes
Answer:
0.720 M/s
Explanation:
Let's consider the following balanced equation.
5Br⁻(aq) + BrO⁻₃(aq) + 6H⁺(aq) → 3 Br₂(aq) + 3H₂O(l)
The molar ratio of Br⁻ to Br₂ is 5:3, that is, when 5 moles of Br⁻ are consumed, 3 moles of Br₂ are produced. If the average rate of consumption of Br⁻ is 1.20 × 10⁻⁴ M/s, the average rate of formation of Br₂ is:

Ngl, there is no picture.
First, in this case, we define the K constant as the solubility of the solute in water divided by the solubility of the solute in ether.
K = (X grams of solute / 75 mL of ethyl ether) / (5 g of solute / 100 mL of water)
K = (X / 75) / (5 / 100)
1 = (X / 75) / (5 / 100)
5 / 100 = X / 75
0,05 = X /75
X = 0,05 × 75 = 3.75 g of solute that will be extracted by the ether