Answer:
The turnover number is the maximum substrate quantitiy converted to product per enzyme and per second. It can be calculate as follows:
with
active enzyme concentration.
In this case we have Vmax an data to calculate ![[E]](https://tex.z-dn.net/?f=%5BE%5D)

Now
it is not like any option.
If we assume that
have the non usual units of
and it is 
So we need divide by the moles of E (in place of [E])
Now 
(pass from
to
dividing by 60)
Hello!
The part of the carbon cycle where humans had the greatest impact is the return of CO₂ to the atmosphere by burning of ancient organic matter.
The ancient organic matter is also called Fossil Fuels. Some Fossil Fuels are Petroleum and Coal. Fossil Fuels are used to power our society and are burned to provide energy for power plants and vehicles, and by burning them, Carbon Dioxide (CO₂) is produced, increasing the natural concentration of this compound in the atmosphere.
Have a nice day!
Answer:
a. NH3 is limiting reactant.
b. 44g of NO
c. 40g of H2O
Explanation:
Based on the reaction:
4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)
4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.
To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:
<em>a. </em><em>Moles NH3 -Molar mass. 17.031g/mol-</em>
25g NH3*(1mol/17.031g) = 1.47moles NH3
Moles O2 = 4 moles
For a complete reaction of 4 moles of O2 are required:
4mol O2 * (4mol NH3 / 5mol O2) = 3.2 moles of NH3.
As there are just 1.47 moles, NH3 is limiting reactant
b. Moles NO:
1.47moles NH3 * (4mol NO/4mol NH3) = 1.47mol NO
Mass NO -Molar mass: 30.01g/mol-
1.47mol NO * (30.01g/mol) = 44g of NO
c. Moles H2O:
1.47moles NH3 * (6mol H2O/4mol NH3) = 2.205mol H2O
Mass H2O -Molar mass: 18.01g/mol-
2.205mol H2O * (18.01g/mol) = 40g of H2O
Answer:
The final pressure is approximately 0.78 atm
Explanation:
The original temperature of the gas, T₁ = 263.0 K
The final temperature of the gas, T₂ = 298.0 K
The original volume of the gas, V₁ = 24.0 liters
The final volume of the gas, V₂ = 35.0 liters
The original pressure of the gas, P₁ = 1.00 atm
Let P₂ represent the final pressure, we get;



∴ The final pressure P₂ ≈ 0.78 atm.