Answer:
P = a(61a - 36b + 50c) + 10b² + 89c² - 16bc
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Terms/Coefficients
- Expand by FOIL (First Outside Inside Last)
- Factoring
<u>Geometry</u>
Perimeter Formula [Triangle]: P = L₁ + L₂ + L₃
- L₁ is one side
- L₂ is another side
- L₃ is the 3rd side
Step-by-step explanation:
<u>Step 1: Define</u>
L₁ = (6a - 3b)(6a - 3b)
L₂ = (5a + 5c)(5a + 5c)
L₃ = (8c - b)(8c - b)
<u>Step 2: Find Perimeter</u>
- Substitute in variables [Perimeter - Triangle]: P = (6a - 3b)² + (5a + 5c)² + (8c - b)²
- Expand [FOIL]: P = (36a² - 36ab + 9b²) + (25a² + 50ac + 25c²) + (b² - 16bc + 64c²)
- Combine like terms (a²): P = 61a² - 36ab + 9b² + 50ac + 25c² + b² - 16bc + 64c²
- Combine like terms (b²): P = 61a² + 10b² - 36ab + 50ac + 25c² - 16bc + 64c²
- Combine like terms (c²): P = 61a² + 10b² + 89c² - 36ab + 50ac - 16bc
- Rearrange variables: P = 61a² - 36ab + 50ac + 10b² + 89c² - 16bc
- Factor: P = a(61a - 36b + 50c) + 10b² + 89c² - 16bc
Answer:
Option (4)
Step-by-step explanation:
By applying triangle sum theorem in ΔABC,
m∠A + m∠B + m∠C = 180°
80° + 40° + m∠C = 180°
m∠C = 180° - 120°
m∠C = 60°
Since, ∠ACB ≅ ∠DCE [Vertically opposite angles]
m∠DCE = m∠ACB = 60°
Now by applying triangle sum theorem in ΔCDE,
m∠DCE + m∠CED + m∠CED = 180°
60° + 70° + x° = 180°
x = 180 - 130
x = 50°
Therefore, Option (4) will be the answer.
I think it’s -2-13x if I’m not mistaken
So if i assume your trying to get 180 Degrees then that means 180-57 degrees = angle 8 which would be 123 degrees.