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3 years ago

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Mathematics

2 answers:

Alla [95]3 years ago

7 0

Each result is equally likely to occur!!

miv72 [106K]3 years ago

6 0

C. theres both a 50/50 chance that you will flip either heads or rails

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sasho [114]

Answer:

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Step-by-step explanation:

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2 years ago

Math - Use unit conversion factor to convert the units.

nlexa [21]

Answer: 240 minutes, 20 cups, 4000 pounds

<u>Step-by-step explanation:</u>

Use the following conversions:

1 hour = 60 minutes

2 cups = 1 pint

2 pints = 1 quart

1 ton = 2000 pounds

$4\ hours\times \dfrac{60\ minutes}{1\ hour}=\large\boxed{240\ minutes}\\\\\\\\5\ quarts \times \dfrac{2\ pints}{1\ quart}\times \dfrac{2\ cups}{1\ pint}=\large\boxed{20\ cups}\\\\\\\\2\ tons\times \dfrac{2000\ pounds}{1\ ton}=\large\boxed{4000\ pounds}$

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2 years ago

You earn 50,000 per year,and paid 10 percent in taxes this year. the government increased the tax rate to 20 percent foe the nex

bulgar [2K]

Answer:

Step-by-step explanation:

he paid 5000 in taxes last year multiply by 2 10000

D is the answer sorry i dont have a proper explanation

4 0

2 years ago

Use the Chain Rule (Calculus 2)

atroni [7]

1. By the chain rule,

$\dfrac{\mathrm dz}{\mathrm dt}=\dfrac{\partial z}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial z}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}$

I'm going to switch up the notation to save space, so for example, $z_x$ is shorthand for $\frac{\partial z}{\partial x}$ .

$z_t=z_xx_t+z_yy_t$

We have

$x=e^{-t}\implies x_t=-e^{-t}$

$y=e^t\implies y_t=e^t$

$z=\tan(xy)\implies\begin{cases}z_x=y\sec^2(xy)=e^t\sec^2(1)\\z_y=x\sec^2(xy)=e^{-t}\sec^2(1)\end{cases}$

$\implies z_t=e^t\sec^2(1)(-e^{-t})+e^{-t}\sec^2(1)e^t=0$

Similarly,

$w_t=w_xx_t+w_yy_t+w_zz_t$

where

$x=\cosh^2t\implies x_t=2\cosh t\sinh t$

$y=\sinh^2t\implies y_t=2\cosh t\sinh t$

$z=t\implies z_t=1$

To capture all the partial derivatives of $w$ , compute its gradient:

$\nabla w=\langle w_x,w_y,w_z\rangle=\dfrac{\langle1,-1,1\rangle}{\sqrt{1-(x-y+z)^2}}}=\dfrac{\langle1,-1,1\rangle}{\sqrt{-2t-t^2}}$

$\implies w_t=\dfrac1{\sqrt{-2t-t^2}}$

2. The problem is asking for $\frac{\partial z}{\partial x}$ and $\frac{\partial z}{\partial y}$ . But $z$ is already a function of $x,y$ , so the chain rule isn't needed here. I suspect it's supposed to say "find $\frac{\partial z}{\partial s}$ and $\frac{\partial z}{\partial t}$ " instead.