A pitcher could hold two-twelfths of a gallon of water.If Roger filled up nine pitches,how much water would he have?
2 answers:
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Answer:
Step-by-step explanation:
we know that
The sides of a rhombus are all congruent and the diagonals are perpendicular bisectors of each other
so
Applying the Pythagorean Theorem
where
c is the length side of the rhombus
a and b are the semi-diagonals
we have
substitute the values
To find out the perimeter of the rhombus multiply the length side by 4
Answer: Check out the diagram below
The reflected image is shown in red.
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Explanation:
Draw a vertical line through -2 on the x axis. This is the mirror line.
Now focus on the upper right corner of the figure, which is at (-3, -1). Notice how the horizontal distance from this corner point to the mirror line is exactly 1 unit. If we move another 1 unit to the right, then we'll arrive at (-1,-1) which is where the reflected point lands or ends up.
In short, the upper right corner point (-3,-1) reflects over x = -2 to land on (-1,-1)
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As another example, the upper left corner point (-5, -1) will move exactly 4 spaces to the right to get to the mirror line. Then we move another 4 spaces to the right to get to (2,-1).
So the upper left corner (-5,-1) will ultimately move to (2,-1) after the reflection over x = -2.
Apply these steps to the other corner points and you'll end up with what is shown below.
Take note that a point like A(-5,-1) moves to A'(1,-1), and similar to the other points as well. Also, notice that when going from A to B to C, etc we are moving clockwise. We move counterclockwise when going from A' to B' to C' etc. Reflections always swap the orientation.
