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Annette [7]
3 years ago
5

A wiper blade of a car is of length 24 cm sweeping through an angle of begin mathsize 18px style text 120° end text end style. T

he total area cleaned at one sweep of the blade is​
Mathematics
1 answer:
dlinn [17]3 years ago
6 0

Answer:

A=603.18\ cm^2

Step-by-step explanation:

The length of a blade, r = 24 cm

The sweeping angle is 120°.

We need to find the total area cleaned at one sweep of the blade. The area of sector is given by :

A=\dfrac{\theta}{360}\times \pi r^2

A=\dfrac{120}{360}\times \pi \times 24^2\\\\=603.18\ cm^2

So, the total area cleaned at one sweep of the blade is 603.18\ cm^2.

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Alex wrote 103.903 in expanded form as 100+3 x 1+9 x 1/100 +3 x 1/1000. Explain his mistake then tell how to correct it.
Damm [24]
Your mistake was in this part  9 x 1/100 . After the decimal point the place value starts with tenths so you should write 9 x 1/10 .

Place values

Before the decimal point

3 ones = 3 x 1

0 tens = 0 x 10

1 hundreds = 1 x 100

After the decimal point

9 tenths = 9 x 1/10

0 hundredths = 0 x 1/100

3 thousandths= 3 x 1/1000

1 x 100 + 0 x 10 + 3 x 1 + 9 x 1/10 + 0 x 1/100 + 3 x 1/1000

  100     +    0     +   3    +    0.9      +     0        +    0.003

           100         + 3      +          0.9                +     0.003 =  103.903

<span> </span>

8 0
3 years ago
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The average annual snowfall in king salmon, Alaska is 45.9 inches. The snow season last about 7 months of a year. About how much
Gelneren [198K]
There is 45.9 inches of snow for the whole year 
so average / month  = 45.9 / 12 =  3.825 inches
7 0
4 years ago
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What is the smallest integer $n$, greater than $1$, such that $n^{-1}\pmod{130}$ and $n^{-1}\pmod{231}$ are both defined?
olasank [31]

First of all, the modular inverse of n modulo k can only exist if GCD(n, k) = 1.

We have

130 = 2 • 5 • 13

231 = 3 • 7 • 11

so n must be free of 2, 3, 5, 7, 11, and 13, which are the first six primes. It follows that n = 17 must the least integer that satisfies the conditions.

To verify the claim, we try to solve the system of congruences

\begin{cases} 17x \equiv 1 \pmod{130} \\ 17y \equiv 1 \pmod{231} \end{cases}

Use the Euclidean algorithm to express 1 as a linear combination of 130 and 17:

130 = 7 • 17 + 11

17 = 1 • 11 + 6

11 = 1 • 6 + 5

6 = 1 • 5 + 1

⇒   1 = 23 • 17 - 3 • 130

Then

23 • 17 - 3 • 130 ≡ 23 • 17 ≡ 1 (mod 130)

so that x = 23.

Repeat for 231 and 17:

231 = 13 • 17 + 10

17 = 1 • 10 + 7

10 = 1 • 7 + 3

7 = 2 • 3 + 1

⇒   1 = 68 • 17 - 5 • 231

Then

68 • 17 - 5 • 231 ≡ = 68 • 17 ≡ 1 (mod 231)

so that y = 68.

3 0
3 years ago
1.) a square has a perimeter of 144 yd. what is the length of each side
Anuta_ua [19.1K]

Answer:

1) 36 yard

2) 2 feet

Step-by-step explanation:

1) Perimeter = 4 * side length

  144 = 4 * s

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2) Area = Length * Length

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8 0
3 years ago
Given that
Sophie [7]

Answer:

  • P = 22

Step-by-step explanation:

<u>We know that:</u>

  • P = 7x + 20 − 2y
  • x = 2
  • y = 6

<u>Work:</u>

  • P = 7x + 20 − 2y

<u>Substituting the given values</u>

  • P = 7(2) + 20 − 2(6)

<u>Solving</u>

  • => P = 14 + 20 - 12
  • => P = 22

Hence, the value of P is 22.

6 0
3 years ago
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