2x+3y=36 when y=6
2x+(3)(6)=36
Simplify
2x+18=36
Subtract 18 from both sides.
2x+18−18=36−18
2x=18
Divide both sides by 2.
2x/2=18/2
x=9
16 2/12
I hope this helps :)
Answer:
Pr(the sum of the numbers rolled is either a multiple of 3 or an even number)=
Step-by-step explanation:
Let A be the event "sum of numbers is multiple of 3"
and B be the event "sum is an even number".
As our dice has six sides, so the sample space of two dices will be of 36 ordered pairs.
|sample space | = 36
Out of which 11 pairs have the sum multiple of 3 and 18 pairs having sum even.
So Pr(A)= 
and Pr(B)= 
and Pr(A∩B) =
, as 5 pairs are common between A and B.
So now Pr(A or B)= Pr(A∪B)
= Pr(A)+Pr(B) - Pr(A∩B)
=
+
- 
= 
= 
Answer:
12n + 60
General Formulas and Concepts:
<u>Pre-Algebra</u>
Distributive Property
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
(n + 12) × 5 + 7n
<u>Step 2: Simplify</u>
- Distribute 5: 5(n) + 5(12) + 7n
- Multiply: 5n + 60 + 7n
- Combine like terms: 12n + 60