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4 years ago

7

What is the answer to -3/4 (2)(-6) in fraction form

1 answer:

nasty-shy [4]4 years ago

4 0

I'm assuming the question looks like this?

$\frac{-3}{4} (2)(-6)$

If so then the answer should be:

$\frac{-3}{4} (2)(-6)=\frac{-3}{4} (-12)=9$

Hope this helps!

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The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

On Monday there were 25 students that came to school, on Tuesday there was a 20% in

madreJ [45]

Answer:

there are 20 students in attendance on tuesday

Step-by-step explanation:

20% of 25 is twenty

6 0

3 years ago

Quanto fa 5+5<br><br> Quanto fa 5+5

Irina-Kira [14]

Answer:

10

Step-by-step explanation:

5+5=10

8 0

3 years ago

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Brian's kite is flying above a field at the end of a 68m string.If the angle of elevation to the kite measures 70 degrees,how hi

Dvinal [7]

Answer:

$h = 63.92\ m$

Step-by-step explanation:

Given:

Angle of elevation = 70°

Length of string = 68 m

We need to find the height of the kite.

Solution:

Requirement figure attached in file.

Where:

BC = 68 m

AC = h (Height of the kite)

∠ABC = 70°

Using Cosine rule to find the height of the kite.

$AC = BC\times sin(70)$

$h = 68\times 0.94$

$h = 63.92\ m$

Therefore, height of the kite from Brian's head $h = 63.92\ m$ .

4 0

4 years ago

(x-7) (-9) + (x-7) ( 4x+5)

Oksana_A [137]

Answer:

4x^2−32x+28

Step-by-step explanation:

3 0

3 years ago

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