Given:
Uniform distribution of length of classes between 45.0 to 55.0 minutes.
To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:
45+55/2 = 50
So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />
Answer:
22.21 m/s
Step-by-step explanation:
1 hour = 80km
1 minute = 80000 ÷ 60 = 1.333km
1 second = 1.333 ÷ 60 = 22.21
The first answer.
Point P is at (50,-40) the distance from Q to P is 80 units which you can find by subtracting the x of Q (-30) from the x of P (50).
50-(-30)=80
It then tells you point R is vertically above point Q so you know your x value for R will be the same as Q.
Add your distance from Q to P of 80 units to the y value of Q because you are traveling up.
-40+80=40
R will have a point of (-30,40) and a distance of 80 units
Answer:
No answer
Step-by-step explanation:
5x-20-X+9
7x-20+9
7x-11
You want to know the factor by which 3 2/3 is multiplied to get 7 1/3.
1. You can estimate that it is 2 from 7/3 ≈ 2, then check by multiplication to see if that is right.
.. 2*(3 2/3) = 6 4/3 = 7 1/3 . . . . 2 is the correct factor.
2. You can divide 7 1/3 by 3 2/3 to see what the factor is.
.. (7 1/3)/(3 2/3) = (22/3)/(11/3) = 22/11 = 2 . . . . 2 is the factor Earl used.
3. You could see how many times you can subtract 3 2/3 from 7 1/3.
.. 7 1/3 -3 2/3 = (7 -3) +(1/3 -2/3) = 4 -1/3 = 3 2/3 . . . . . subtracting once gives 3 2/3
.. 3 2/3 -3 2/3 = 0 . . . . . . subtracting twice gives 0, so the factor is 2.
4. You could add 3 2/3 to see how many times it takes to get 7 1/3.
.. 3 2/3 +3 2/3 = (3 +3) +(2/3 +2/3) = 6 +4/3 = 7 1/3
We only need to add two values of 3 2/3 to get 7 1/3, so the factor is 2.
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We have shown methods using multiplication, division, subtraction, addition. Take your pick.
