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3 years ago

7

(Please look at the NUMBERS below the picture)

1 answer:

GenaCL600 [577]3 years ago

7 0

This is what I got
Area= 31.83 rounded would be 32
Radius= 3.18 rounded would be 3
Diameter= 6.37 rounded would be 6

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Plz do both of them for me and even show the work plzzzzzz

Vinvika [58]

Answer:

(a)= option 3

(b)= option 3

Step-by-step explanation:

(A) It is given that a sequence is defined by the recursive function $a_{1}=1$ and $a_{n}=a_{n-1}+n$

Now, substituting the value of n=2 in above equation,

$a_{2}=a_{1}+2$

$a_{2}=1+2$

$a_{2}=3$

Again putting n=3,

$a_{3}=a_{2}+3$

$a_{3}=3+3$

$a_{2}=6$

Putting n=4,

$a_{4}=a_{3}+4$

$a_{4}=6+4$

$a_{4}=10$

Putting n=5,

$a_{5}=a_{4}+5$

$a_{5}=10+5$

$a_{5}=15$

Putting n=6,

$a_{6}=a_{5}+6$

$a_{6}=15+6$

$a_{6}=21$

Putting n=7,

$a_{7}=a_{6}+7$

$a_{7}=21+7$

$a_{7}=28$

Hence, option 3 is correct.

(B) The given sequence is :

5, -10, 20, -40, 80.....

Since, the given sequence is GP, therefore

$a_{1}=5$ and r=-2

The nth term is given by:

$a_{n}=a_{1}r^{n-1}$

For fifteenth term, put n=15 in above equation, we get

$a_{15}=5(-2)^{14}$

= $5{\times}16384$

= $81920$

Hence, the fifteenth term is 81920.

Option 3 is correct.

5 0

3 years ago

A radio active isotope decays according to the exponential decay equation where t is in days. Round to the thousandths place. Th

Whitepunk [10]

To calculate the value of the half life we proceed as follows;
a/2=ae^(-2.360t)
the a(s) will cancel and we shall remain with:
1/2=e^-2.360t
introducing the natural logs we get:
ln (1/2)=ln e^(-2.360t)
ln(1/2)=-2.360t
hence;
t=(ln 0.5)/(-2.360)
t=0.294
the answer is t=0.294

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3 years ago

Can someone help me with this ?

Gala2k [10]

Answer:

de goes with bc ab goes with fd and angle f is angle A and angle d is angle B

Step-by-step explanation:

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3 years ago

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Solve kx + 8 = 4 for x.

Harlamova29_29 [7]

K×x+8=4
k×x=4-8
k×x=-4
x=-4/k

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3 years ago

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If x=6 find the value of x/2

nekit [7.7K]

Answer:

3

Step-by-step explanation:

6/2=3

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3 years ago

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