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Leya [2.2K]
2 years ago
7

Please help due today!

Mathematics
1 answer:
fgiga [73]2 years ago
6 0

Answer:

ok i dont want to help you dufus

Step-by-step explanation:

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HELP PLEASE!! Algebra II
butalik [34]

Answer:

Step-by-step explanation:

J is correct.. that function can never be less than 2

7 0
2 years ago
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X/-9 =3<br>I dont understand this.​
STatiana [176]

Final Answer: x = -27

Steps/Equations:

Question: \frac{x}{-9} = 3

Step 1: Move the negative sign to the left side.

-\frac{x}{9} = 3

Step 2: Multiply both sides by 3.

-x = 3 * 9

Step 3: Simplify 3 * 9 to 27.

-x = 27

Step 4: Multiply both sides by -1.

x = -27

~I hope I helped :)~

5 0
2 years ago
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P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
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Solve the equation for y 2x+6y=13
m_a_m_a [10]
I hope this helps you



6y=13-2x


y=13-2x/6


y=13/6-1/3x
8 0
3 years ago
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Select all of the coefficients in the expression.<br> 12xy3 + 2x5y + 4x5y2 + 7x5y.
DedPeter [7]

Answer:

The coefficients are simply 12, 2, 4, and 7.

Step-by-step explanation:

Coefficients are the numbers that come before terms. Each term has a coefficient before it.

5 0
3 years ago
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