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2 years ago

7

Please help due today!

1 answer:

fgiga [73]2 years ago

6 0

Answer:

ok i dont want to help you dufus

Step-by-step explanation:

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HELP PLEASE!! Algebra II

butalik [34]

Answer:

Step-by-step explanation:

J is correct.. that function can never be less than 2

7 0

2 years ago

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X/-9 =3<br>I dont understand this.

STatiana [176]

Final Answer: $x = -27$

Steps/Equations:

Question: $\frac{x}{-9} = 3$

Step 1: Move the negative sign to the left side.

$-\frac{x}{9} = 3$

Step 2: Multiply both sides by $3$ .

$-x = 3 * 9$

Step 3: Simplify $3 * 9$ to $27$ .

$-x = 27$

Step 4: Multiply both sides by $-1$ .

$x = -27$

~I hope I helped :)~

5 0

2 years ago

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P³ = 1/8 please help me if anybody can .

ivanzaharov [21]

Answer:

$p= \dfrac{1}{2}$

Step-by-step explanation:

Given equation:

$p^3=\dfrac{1}{8}$

Cube root both sides:

$\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}$

$\implies p= \sqrt[3]{\dfrac{1}{8}}$

$\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:$

$\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}$

$\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:$

$\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}$

$\textsf{Apply exponent rule} \quad 1^a=1:$

$\implies p= \dfrac{1}{8^{\frac{1}{3}}}$

Rewrite 8 as 2³:

$\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}$

$\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}$

Simplify:

$\implies p= \dfrac{1}{2^{\frac{3}{3}}}$

$\implies p= \dfrac{1}{2^{1}}$

$\implies p= \dfrac{1}{2}$

3 0

1 year ago

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Solve the equation for y 2x+6y=13

m_a_m_a [10]

I hope this helps you

6y=13-2x

y=13-2x/6

y=13/6-1/3x

8 0

3 years ago

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Select all of the coefficients in the expression.<br> 12xy3 + 2x5y + 4x5y2 + 7x5y.

DedPeter [7]

Answer:

The coefficients are simply 12, 2, 4, and 7.

Step-by-step explanation:

Coefficients are the numbers that come before terms. Each term has a coefficient before it.

5 0

3 years ago

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