Given the following trapezoid, if QR=8 and UT=12, find the length of the midsegment VS?
1 answer:
Answer:
The midsegment of a trapezoid is the average of the two bases.
VS=(QR+UT)/2=10
Step-by-step explanation:
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The slope is 0 and the equation of the line is y= -2.
Answer:
60+61+62= 183
Step-by-step explanation:
x + x-+1 + x+2 = 183
3x +3 = 180
3x =180
x=60
I think it is fifty-four hundred