Answer:
0.00085714285
Step-by-step explanation:
it would take way to long to explain maybe search it up? but that is the answer
A population of size P increasing at the rate of 2% may be modelled as follows
P = P0<span> e</span>0.02 t<span> , where t is the number of years after t = 0 and P</span>0<span> is the population at t = 0. </span>
Let t = 0 corresponds to January 1, 2000 and therefore t = 4 corresponds to December 31. But P is 2,000,000 when t = 4. Hence
2,000,000 = P0<span> e</span>0.02*4
<span>Solve the above for P0</span>
P0<span> = 2,000,000 / e</span>0.02*4<span> = 1 846 000 (rounded to the nearest thousand) </span>
<span>P0 is the population at t = 0 or on January 1, 2000.
A. is the correct answer</span>
Y=10x+250
The slope represents the amount of money added in per month, and the y-intercept represents the original amount.
Hope this helps!
The slope is roughly -6/1
I graphed the equation y= -6/1x+4 and it looked pretty similar to the graph on your screen I hope this helps :)
The answer is the last one
