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Rudiy27
2 years ago
14

Help me? shhhhh.....its for a test

Mathematics
2 answers:
Lena [83]2 years ago
6 0

Answer:

1/5

Step-by-step explanation:

Mekhanik [1.2K]2 years ago
3 0

Answer:

2/9

Step-by-step explanation:

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Write the improper fraction 31/20 as a mixed number?
sveta [45]
\dfrac{31}{20}=\dfrac{20+11}{20}=\dfrac{20}{20}+\dfrac{11}{20}=1\dfrac{11}{20}
7 0
2 years ago
Given the function h(x)=x^2-7x+6h(x)=x
Goryan [66]

Answer:

0 (no change)

Step-by-step explanation:

Recall that the average rate of change of a function f(x) over the interval [a,b] is equal to \frac{f(b)-f(a)}{b-a}:

\frac{h(b)-h(a)}{b-a}\\ \\\frac{h(6)-h(1)}{6-1}\\\\\frac{0-0}{5}\\ \\0

Hence, the average rate of change of the function h(x) over the interval [1,6] is 0, or no change.

3 0
1 year ago
THIS IS DUE TODAY PLS PLS PLS HELP ME ON IT :(
Rufina [12.5K]

Answer:

monke

Step-by-step explanation:

monkey

7 0
2 years ago
Read 2 more answers
PLEASE HELP THIS WAS SUPPOSED TO BE TURNED IN BY 12:00
Strike441 [17]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How would you use the Fundamental Theorem of Calculus to determine the value(s) of b if the area under the graph g(x)=4x between
-BARSIC- [3]
The Fundamental Theorem of Calculus regarding geometry states that 
\int\limits^b_a g{(x)} \, dx = F(b)-F(a)

Where F is the indefinite integral of g(x)

The first step is to integrate g(x)
\int\ {4x} \, dx = \frac{4x^{1+1} }{1+1} = \frac{4x^{2} }{2} =2 x^{2}

Then substitute the value of b and a=1 into 2x^{2}

[2 (b)^{2}]-[2 (1)^{2}] = 240
2b^{2} -2=240
2b^{2}=240+2
2b^{2}=242
b^{2}= \frac{242}{2}
b^{2}=121
b=11

Hence the limit of the area under g(x) is between a=1 and b=11

6 0
2 years ago
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