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kaheart [24]
3 years ago
11

Is the number of members of Club X greater than the number of members of Club Y ? (1) Of the members of Club X, 20 percent are a

lso members of Club Y. (2) Of the members of Club Y, 30 percent are also members of Club X.
Mathematics
1 answer:
Oliga [24]3 years ago
7 0

Answer:

Yes

Step-by-step explanation:

The 20% of members of club X that are also members of club Y can be written as: P(Y/X) = 20% (that is, the probability of belonging to Y given that it belongs to X)

The 30% of members of club Y that are also members of club X can be written as: P(X/Y) = 30% (that is, the probability of belonging to X given that it belongs to Y)

The formula of conditional probability of A given B is  

P(A/B) = (A∩B) / P(A)

Where (A∩B) is the probability that both events A and B occur and P(A) is the probability of A.

Based on that, we can write,

P(Y/X) = P(Y∩X) / P(X) = 20 % = 0.2

P(X/Y) = P(Y∩X) / P(Y) = 30 % = 0.3

Clearing P(Y∩X) of both equations and equalizing,

P(Y/X).P(X) = P(X/Y).P(Y)

Moving terms ,

P(X) / P(Y) = P(X/Y) / P(Y/X) = 0.3 / 0.2 = 1.5

That is, P(X) is 1.5 times P(Y), which means that the amount of members of X is greater than the members of Y.  

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3 years ago
Is a triangle with sides of length 6ft, 21 ft, 23 ft. A right triangle?
gayaneshka [121]

Answer:

No

Step-by-step explanation:

By using the Pythagoras theorem, it can be easily determined that whether the triangle is right triangle or not.

Thus, a^{2}+b^{2}=c^{2} where where a and b are the legs and c is the hypotenuse.

Let a=6ft, b=21ft and c=23ft, then

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which is not possible, therefore the given triangle is not right triangle because it does not satisfy the Pythagoras theorem.


7 0
3 years ago
Can the numbers 24,32,40 be the lengths of three sides of a right triangle?
Naddika [18.5K]

Answer:

Yes

Step-by-step explanation:

using pythagorus theorum:   a^{2} + b^{2} = c^{2}

24^{2} +32^{2} =  1024+576

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