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3 years ago

What is the domain and range of the set of ordered pairs?

Mathematics

1 answer:

Delvig [45]3 years ago

5 0

Answer:

D) would be the answer

Step-by-step explanation:

Domain is always the set of x-coordinates in the pairs and the range is always the set of y-coordinates in the pairs.

D: 7, -2, 4, -9, 0

R: 3, -2, 1, 0, 7

Put them in order from least to greatest.

D: -9, -2, 0, 4, 7

R: -2, 0, 1, 3, 7

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Simplify . 16x3y2/36xy2z3

dezoksy [38]

$\frac{16 {x}^{3} {y}^{2} }{36x {y}^{2} {z}^{3} } = \frac{4 {x}^{2} }{9 {z}^{3} } \\ \frac{ {x}^{a} }{ {x}^{b} } = {x}^{a - b} \\ {x}^{ - a} = \frac{1}{ {x}^{a} }$

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3 years ago

in a test correct answer are given positive numbers and for incorrect negative numbers jack scored in successive rounds were-65,

eimsori [14]

Answer:

<em>Jack scored a total of -40</em>

Step-by-step explanation:

<u>Arithmetic</u>

Jack took a test where the correct answers are given as positive numbers and the incorrect answers are negative numbers.

The scores were

-65,-10,-15,20,30

The total score is the arithmetic sum of all scores, including their signs:

Total score: -65-10-15+20+30

Total score: -40

Jack scored a total of -40

4 0

3 years ago

Why is “h” negative in math

tresset_1 [31]

Answer:

Just remember that when it comes to vertex form and parabola transformations a negative h means shift right and positive h left. We anumberd to the number lgraphbitself itself having negative integers on left and positive on right and I can see why this throws people off.

Step-by-step explanation:

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3 years ago

Read 2 more answers

Match the correct angle measurement with its letter from the diagram.

igor_vitrenko [27]

Answer:

<C=48 because 90-42=42 as in the other side of the triangle.

<B=42 because vertical angles are always congruent.

<B+<D=90 because <D is 48 because it is vertical to <C

5 0

2 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

3 years ago

What is the domain and range of the set of ordered pairs?​

What is the domain and range of the set of ordered pairs?