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3 years ago

Determine the measure of angle a. PLEASE HELP ASAP!

Mathematics

1 answer:

wlad13 [49]3 years ago

6 0

Answer:

Step-by-step explanation:

Remember that the sum of the interior angles of a triangle will always total 180.

Therefore:

$(9x+6)+(74)+(16x)=180\\$

Let’s solve for <em>x: </em>

Combine LIke Terms:

$(9x+16x)+(74+6)=180$

Add:

$25x+80=180$

Subtract 80 from both sides:

$25x=100$

Divide both sides by 25:

$x=4$

Therefore, the value of <em>x </em>is 4.

Now, to find A, we can substitute it for A.

A is measured by:

$\angle A=9x+6$

Substitute 4 for <em>x</em> and evaluate:

$\angle A=9(4)+6=36+6=42\textdegree$

Hence, our answer is D.

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If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers

X - y= -4 -2x +3y =6

STatiana [176]

Answer:

<em><u>x=-6, y=-2</u></em>, (As a point) (-6, -2).....The point form is not necessary unless you want to solve the system (of equations) by graphing.

Step-by-step explanation:

By substitution:

x-y=-4 By adding y on both sides,

x=y-4

Now you can substitute x for the expression (y-4)

Plug the (y-4) as x in the other equation.

So -2x+3y=6 becomes

-2(y-4)+3y=6

Now solve:

-2(y-4)+3y=6 distributes out to be

-2y+8+3y=6 Now combining like terms

y+8=6 Subtract 8 on both sides to isolate the variable

Now plug the value -2 in where the y is in any equation (preferably the easier/less complicated one) and solve for x.

So x-y=-4 becomes

x-(-2)=-4

=x+2=-4

=<u><em>x=-6</em></u>

3 0

2 years ago

Points A, B, C and D have coordinates A(5, 7), B(7, 1), C(17, m) and D(−1, 3). If line

STatiana [176]

Answer:

Step-by-step explanation:

I used a graph

6 0

2 years ago

Read 2 more answers

Hewo Pls Answer the questions below TY!

Musya8 [376]

Answer:

dont worry if people report you for a answer that is not right lol trust me i know

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Are these triangles similar? if so, what postulate or theorem justifies that they are similar?

Karo-lina-s [1.5K]

Answer:

Yes The triangles are similar by SAS Similarity Theorem

Step-by-step explanation:

we know that

<u>Side-Angle-Side Similarity,</u> states that If an angle of a triangle is congruent to an angle of another triangle and if the included sides of these angles are proportional, then the two triangles are similar

In this problem

Angle L is congruent with Angle Z

Verify if the included sides are proportional

$\frac{LJ}{ZY}=\frac{KL}{XZ}$

substitute the values

$\frac{3}{1.5}=\frac{4}{2}$

$2=2$ -----> is true

therefore

The triangles are similar by SAS

7 0

3 years ago