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olga nikolaevna [1]
3 years ago
8

Please awnser asap asap

Mathematics
1 answer:
netineya [11]3 years ago
8 0

9514 1404 393

Answer:

  h > 0, only integers

Step-by-step explanation:

One can only buy integer numbers of packages of hotdogs, so the domain is integer values.

Since we "must" buy more than 0 packages, the appropriate domain specification is ...

  h > 0, only integers

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What is the best approximation for the input value when f(x)=g(x)?
Lostsunrise [7]

Answer:

x=0 and x=1.

Step-by-step explanation:

If we have to different functions like the ones attached, one is a parabolic function and the other is a radical function. To know where f(x)=g(x), we just have to equalize them and find the solution for that equation:

x^{2}=\sqrt{x} \\(x^{2} )^{2}=(\sqrt{x} )^{2}\\x^{4}=x\\x^{4}-x=0\\x(x^{3}-1)=0\\

So, applying the zero product property, we have:

x=0\\x^{3}-1=0\\x^{3}=1\\x=\sqrt[3]{1}=1

Therefore, these two solutions mean that there are two points where both functions are equal, that is, when x=0 and x=1.

So, the input values are  x=0 and x=1.

8 0
3 years ago
Read 2 more answers
Solve for F in the formula C= 5/9 (F-32)
Delvig [45]
F
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7 0
3 years ago
Arlen has a recipe for lasagna that serves 8 people and uses 2 teaspoons of garlic. How many teaspoons of garlic will be used to
Y_Kistochka [10]
Your answer is A) 1 teaspoon.

The ratio for this problem is 8, 2, where 8 is the people, and 2 is the teaspoons. 4 people is half of 8 when you divide 8/4 so you have to do the same with the other part of the ratio. when you split 2 in half, you get 1 teaspoon as your answer

Hope this helps :)
3 0
3 years ago
Suppose that 4 fair coins are tossed. Let Equals The event that exactly 2 coins show tails and Equal The event that at least 2 c
faust18 [17]

Answer:

a) P ( E | F ) = 0.54545

b) P ( E | F' ) = 0

Step-by-step explanation:

Given:

- 4 Coins are tossed

- Event E exactly 2 coins shows tail

- Event F at-least two coins show tail

Find:

- Find P ( E |  F )

- Find P ( E | F prime )

Solution:

- The probability of head H and tail T = 0.5, and all events are independent

So,

                    P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT)  = 6*(1/2)^4 = 0.375

                    P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)

      = 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875

- The probabilities for each events are:

                    P ( E ) = 0.375

                    P ( F ) = 0.6875

- The Probability to get exactly two tails given that at-least 2 tails were achieved:

                    P ( E | F ) = P ( E & F ) / P ( F )

                    P ( E | F ) = 0.375 / 0.6875

                    P ( E | F ) = 0.54545

- The Probability to get exactly two tails given that less than 2 tails were achieved:

                    P ( E | F' ) = P ( E & F' ) / P ( F )

                    P ( E | F' ) = 0 / 0.6875

                    P ( E | F' ) = 0                

6 0
3 years ago
Hey, this is homework that is due today❤️ feel free to help thank you ☺️ have a g❤️❤️d day☺️
MAVERICK [17]

Answer:

About $1.82

Step-by-step explanation:

3 0
3 years ago
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