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adell [148]
2 years ago
14

PLEASE HELP!! DUE SOON!!

Mathematics
1 answer:
mr Goodwill [35]2 years ago
7 0

Answer:

w

Step-by-step explanation:

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Evaluate -a - 12a 2 for a = -1
Serhud [2]
The answer is -11
You put "-1" in place of all the "a"s and get 
-(-1) - 12(-1)^2
-(-1) is just 1, and (-1)^2 is "1"
We are then left with 1-12(1) which is 1-12 which is -11
6 0
3 years ago
(3 x 10-7) x (8 x 10 )
charle [14.2K]

Answer:

1840

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
I need help with this question
Sonbull [250]

= 4 (6) - 4 (√2) + √2 (6) - √2 <span>√2
</span>= 24 - 4√2  + 6√2 - 2 
= (24 - 2)  +  (- 4√2  + 6√2)
= 22 + √2(- 4 + 6)
= 22 + √2 (2)
= 22 + 2√2

hope it helps
5 0
3 years ago
What value of h makes the statement true? (17+h)+(–9) = 17+(5+(–9))
aalyn [17]
I know this is late and you probably got the answer but just in case its C. 5. :P
5 0
3 years ago
According to a recent study of 7335 young people in the US, 30% had been arrested for a crime other than a traffic violation by
victus00 [196]

Answer:

a) Statistic.

b) The population proportion is expected to be between 0.29 and 0.31 with a 94% degree of confidence.

Step-by-step explanation:

a) The proportion of 30% is a statistic, as it is a value that summarizes data only from the sample taken in the study from USA Today. Other samples may yield different proportions.

b) We can use the statistic to estimate a confidence interval for the parameter of the population.

The standard error for the proportion is calculated as:

\sigma_p=\sqrt{\dfrac{p(1-p)}{N}}=\sqrt{\dfrac{0.3\cdot 0.7}{7335}}=\sqrt{2.83\cdot10^5}= 0.00535

The margin of error is 0.01. We can use this value to determine the level of confidence that represents.

The formula for the margin of error is:

E=z\cdot \sigma_p=0.01\\\\z\cdot 0.0535=0.01\\\\z=1.87

This z-value, according to the the standard normal distribution, corresponds to a confidence interval of 94%.

The interval for this margin of error is:

p-E\leq \pi \leq p+E\\\\0.30-0.01\leq \pi \leq 0.30+0.01\\\\0.29\leq \pi \leq 0.31

Then, we can conclude that the population proportion is expected to be between 0.29 and 0.31 with a 94% degree of confidence.

3 0
3 years ago
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