Answer:
8.9 = z
Step-by-step explanation:
11 = 2.1 + z - subtract the 2.1 from the 11
Answer:
Could you please help me with the two most recent questions of mine on my page? I will give u brainliest and 20 points! :))) X
Step-by-step explanation:
<u>Given</u><u> </u><u>that</u><u> </u>
- Height of container is 20 inches .
- Radius of base is 10 inches .
<u>To</u><u> </u><u>Find</u><u> </u>
<u>Formul</u><u>a</u><u> </u>
- Volume of cylinder is πr²h
<u>Solu</u><u>tion</u><u> </u>
→ Volume = πr²h
<u>Usin</u><u>g</u><u> </u><u>π</u><u> </u><u>as</u><u> </u><u>3</u><u>.</u><u>1</u><u>4</u><u> </u>
→ 3.14 × 10 × 10 × 20 = Volume
→ 314 × 20 = Volume
→ <u>6</u><u>2</u><u>8</u><u>0</u><u> </u><u>inches²</u><u> </u><u>is</u><u> </u><u>the holding capacity of the</u><u> container</u><u>. </u><u> </u>
First, you find out how much can be filled in 1 minute. Then you divide that into 120 to get your answer.
To find out how much can be filled in 1 minute, take the time and divide it into the volume. We'll use the second row (2 minutes and 8 gallons.)
8/2=4. So it takes 1 minute to fill 4 gallons. Now, you just divide 4 into 120.
120/4=30
It takes 30 minutes to fill the pool up to 120 gallons.
If I'm reading your equations correctly, they are:f(x)=x2-8x+15g(x)=x-3h(x)=f(x)/g(x)The domain of a function is the set of all possible inputs, what we can plug in for our variable.The largest two limitations on domains (other than explicit limitations, like in piecewise functions) are radicals and rational functions. With radical expressions we know that we CANNOT take an even root of a negative number. I don't see that problem here. With rationals we know that we CANNOT divide by zero. So the question becomes, when does h(x) ask us to divide by zero? When is the denominator of h(x) zero?Since the denominator of h(x) is g(x), we cannot let g(x) equal zero. So when does that happen? when x-3=0 or when x=3. I hope you see here that if x=3, then g(x)=0, and so h(x)=f(x)/0, which we CANNOT do. The domain of h(x) is all real numbers not equal to 3. There is more going on here. If you had factored f(x) first, you could have written h(x) in a confusing way:h(x)=( f(x) ) / ( g(x) )h(x)= ( (x-5)(x-3) ) / (x-3) Right here, it looks like (x-3) will cancel out from the top and bottom of your fraction. It does, in a way. The graph of h(x) will behave exactly like the line y=x-5, except that it has a hole in it at x=3 (check this! it's cool!)SOOO, the takeaway is that it is better to determine limitations on your domain BEFORE over-simplifying your equations.
