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Harlamova29_29 [7]

3 years ago

11

2 quarts = how many ounces

1 answer:

wariber [46]3 years ago

3 0

Answer:

64 ounces

Step-by-step explanation:

1 quart equals 32 ounces

2 quarts equals 64 ounces

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what is the quotient 4x/x^2+5x-6 divided by x^2-11x+28/x^2+7x+6 in simplified form? state any restrictions on the variable.

Nata [24]

A/b ÷ d/c

a/b * c/d

4x/ x² + 5x -6 * x² + 7x + 6/ x² - 11x + 28 factor

4x/ (x+6)(x-1) * (x+6)(x+1)/ (x-7)(x-4) (x+6) cancels out

4x (x+1) / (x-1)(x-7)(x-4)

6 0

4 years ago

PLEASE HELLP TEN MINUTES LEFT !!!

mamaluj [8]

Answer:

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Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Mr. Ratchett, an elderly American, was found murdered in his train compartment on the Orient Express at 7 AM. When his body was

nasty-shy [4]

Answer: Mr. Ratchett died approximately at 2AM.

Step-by-step explanation: <u>Newton's</u> <u>Law</u> <u>of</u> <u>Cooling</u> shows the cooling rate between a body and the environment, by stating that the rate is proportional to the difference in temperatures between them.

Mathematically, it is represented as:

$\frac{dQ}{dt}=\alpha.A.(T_{s}-T)$

This differential equation solved, gives the solution:

$T(t)=T_{s}+(T_{0}-T_{s})e^{-kt}$

where

$T_{s}$ is temperature of the environment

$T_{0}$ is the initial temperature of the body

k is a parameter dependent of heat transfer coefficient, heat capacity and area of the body

t is time required to change the temperature

For the murder on the Orient Express, first determine parameter k.

In 1 hour, Mr. Ratchett's body decrease 1°:

$27=22+(28-22)e^{-1k}$

$5=6e^{-k}$

$e^{-k}=\frac{5}{6}$

$ln(e^{-k})=ln(0.834)$

k = 0.1823

Using the parameter, find estimate time:

$28=22+(37-22)e^{-0.1823t}$

$6=15e^{-0.1823t}$

$ln(e^{-0.1823t})=ln(0.4)$

0.1823t = 0.9163

$t=\frac{0.9163}{0.1823}$

t ≈ 5 hours

The body was found at 7AM. So, it took approximately 5 hours to cool down to 28° at that time. Therefore, Mr. Ratchett died at 2AM.

5 0

3 years ago

Find the derivative of the algebraic functions

jek_recluse [69]

Answer:

10) f'(x) = (x² + 6x - 3)/(x + 3)²

11) g'(x) = 1 - csc²x

Step-by-step explanation:

10. f(x) = x(1 - (4/(x + 3))

Expanding gives;

f(x) = x - (4x/(x + 3))

Differentiating gives;

f'(x) = 1 - 4/(x + 3) + 4x/(x + 3)²

Simplifying this gives;

f'(x) = [(x + 3)² - 4(x + 3) + 4x]/(x + 3)²

f'(x) = (x² + 6x + 9 - 4x - 12 + 4x)/(x + 3)²

f'(x) = (x² + 6x - 3)/(x + 3)²

11. g(x) = x + cot x

Rewriting this gives;

g(x) = x + (1/tan x)

We know that derivative of tan x is sec x while derivative of (1/tan x) is -csc²x

Thus;

g'(x) = 1 - csc²x

This can be written as

Differentiating this gives;

g'(x) = 1 - csc²x

5 0

3 years ago

What is the answer to , solve for W : 2E=6W

mixas84 [53]

Answer: 1/3 E = W
Not sure if that's correct

5 0

3 years ago