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zhannawk [14.2K]
3 years ago
13

Find the value of the expression v + 9 for v = 7.

Mathematics
2 answers:
mel-nik [20]3 years ago
7 0

Answer:

16

Step-by-step explanation:

Since v=7, put 7 where the v is. 7+9=16.

(hope this helps :P)

Masja [62]3 years ago
6 0

Answer:

16

Step-by-step explanation:

1. substitute 7+9=?

2. add 7+9=16

3. find answer 16

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Ierofanga [76]

Answer:

Second box

Third box

fifth box

Step-by-step explanation:

4 0
3 years ago
I need help asap please choose all
lubasha [3.4K]

Answer:

28X-8 & 4x 7X- 4x2 for the first one

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Step-by-step explanation:

Hope this helps have a great day

3 0
4 years ago
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Find the volume of the largest circular cone that can<br> beinscribed in a shpere of radius 3.
Aleksandr [31]

Answer:

V =\dfrac{32}{3}\pi

Step-by-step explanation:

given,

radius of sphere = 3

volume of cone:

V = \dfrac{1}{3}\pi r^2h

r is the radius of circular base

h is the height of the cone

here r = x and h = 3 + y

now, volume in term of x and y

V = \dfrac{1}{3}\pi x^2(3+y)

Applying Pythagoras theorem

x² + y² = 3²

x = \sqrt{9-y^2}

V = \dfrac{1}{3}\pi ( \sqrt{9-y^2})^2(3+y)

V = \dfrac{1}{3}\pi ( 9-y^2)(3+y)

V = \dfrac{1}{3}\pi (27 + 9 y - 3 y^2-y^3)

differentiating both side

\dfrac{dV}{dy} =\dfrac{1}{3}\pi ( 9-6y- 3y^2)

for maxima  \dfrac{dV}{dy} = 0

\pi ( 3-2 y - y^2)=0

 y² + 2 y - 3 = 0

(y+3)(y-1)=0

 y = 1,-3

y cannot be negative so, volume at y = 1

V = \dfrac{1}{3}\pi (27 + 9 (1)- 3(1)^2-(1)^3)

V =\dfrac{32}{3}\pi

Hence, the largest cone which can be inscribed in the spheres of the radius 3 has volume  V =\dfrac{32}{3}\pi

5 0
3 years ago
What is (x-8)(x+4)+(x-3)(x+9)?<br><br>A: 2x²-2x-59<br>B: 2x²+2x-59<br>C: x²-2x-59<br>D: x²+2x-59​
Vikki [24]

Answer:

The answer is B. 2x^2 + 2- 59

Step-by-step explanation:

When you simplify (X-8)(x+4)+(x-3)(x+9) your will get the answer i got.

I hope ive helped you :)

3 0
3 years ago
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Alex_Xolod [135]
1 represent the number of apples at the start.
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