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igomit [66]
3 years ago
13

Can anyone help with these 4 questions?

Mathematics
2 answers:
Zepler [3.9K]3 years ago
7 0
1. 60°
2. 120°
3. 96°
4. 90-50=40°

4 is a complimentary angle
Mnenie [13.5K]3 years ago
3 0

Answer:

hablas español?? Si o no ?

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Simplify the expression.
butalik [34]
Hey there! :D

That's like saying:

-2*-2*-2

-2*-2=4

4*-2= 8

"D" -8 <== the answer 

I hope this helps!
~kaikers
8 0
3 years ago
Read 2 more answers
Can someone please show me how<br><br> 19169000*e^(0.15)= 222712201<br><br> When e= 2.7182818284?
Ierofanga [76]

Answer:

It doesn't. x = 22 271 201

Step-by-step explanation:

You are going to need a calculator no matter how you do it.

x =19 169 000 \times e^{0.15}

(a) The direct method

x = 19 169 000\times 2.718 281 828^{0.15} = 19 169 000 \times 1.161 834 243 = 22 271 201

(b) The indirect method

\ln \left (19 169 000\times 2.718 281 828^{0.15} \right ) = \ln(19 169 000) + 0.15 = 16.768 805 + 0.15 = 16.918 804\\\\e^{16.918 804} = 22 271 201

8 0
3 years ago
Find the minimum sample size when we want to construct a 90% confidence interval on the population proportion for the support of
kogti [31]
N = 73
Hope this helps
4 0
3 years ago
Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result
Vaselesa [24]

<u>Complete Question:</u>

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

<u>Correct Answer:</u>

A) (10-x)(12-x)=15

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

<u>Step-by-step explanation:</u>

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

length=10-x\\breadth=12-x

According to question , Area of new image is :

⇒ Area = \frac{1}{8}Length(breadth)

⇒ Area = \frac{1}{8}(10)(12)

⇒ Area = 15

So the equation will be :

⇒ (10-x)(12-x)=15

b. Find the dimensions of the reduced image

Let's solve :  (10-x)(12-x)=15

⇒ 120-10x-12x+x^2=15

⇒ 120-22x+x^2=15

⇒ x^2-22x+105=0

By Quadratic formula :

⇒ x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x = \frac{22 \pm8 }{2}

⇒ x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}

⇒ x = 15 , x =7

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ x =7

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

5 0
3 years ago
If y varies directly as x and y = 5.5 when x = 11, find x when y = 3.5
PtichkaEL [24]

Answer:

x=7

Step-by-step explanation:

y=mx

5.5=m×11

5.5÷11=m

m=1/2

y=mx

3.5=1/2×x

3.5÷1/2=x

x=7

4 0
3 years ago
Read 2 more answers
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