Answer:
The probability that x will take on a value between 120 and 125 is 0.14145
Step-by-step explanation:
For uniform distribution between a & b
Mean, xbar = (a + b)/2
Standard deviation, σ = √((b-a)²/12)
For 110 and 150,
Mean, xbar = (150 + 110)/2 = 130
Standard deviation, σ = √((150-110)²/12 = 11.55
To find the probability that x will take on a value between 120 and 125
We need to standardize 120 & 125
z = (x - xbar)/σ = (120 - 130)/11.55 = - 0.87
z = (x - xbar)/σ = (125 - 130)/11.55 = - 0.43
P(120 < x < 125) = P(-0.87 < x < -0.43)
We'll use data from the normal probability table for these probabilities
P(120 < x < 125) = P(-0.87 < x < -0.43) = P(z ≤ -0.43) - P(z ≤ -0.86) = 0.33360 - 0.19215 = 0.14145
Hope this Helps!!!
Choose your points, go up from the y intercept to a chosen x point. Then go over the the x point. Up and over is the formula I use.
Answer:
multiply it by 2
Step-by-step explanation:
Answer:
Yes.
Step-by-step explanation:
By adding like terms, -x - 2x = -3x. Therefore, they are equivalent.
Answer:
The probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:

The standard deviation of this sampling distribution of sample proportion is:

Let <em>p</em> = the proportion of keypads that pass inspection at a cell phone assembly plant.
The probability that a randomly selected cell phone keypad passes the inspection is, <em>p</em> = 0.77.
A random sample of <em>n</em> = 111 keypads is analyzed.
Then the sampling distribution of
is:

Compute the probability that the proportion of passed keypads is between 0.72 and 0.80 as follows:


Thus, the probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.