All categories

3 years ago

171

Mathematics

1 answer:

sdas [7]3 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

Convert 1/15 into a decimal correct to 2 decimal places

Citrus2011 [14]

Answer:

$\frac{1}{15} = 0.\overline{66}$

Step-by-step explanation:

We proceed to show the procedure to calculate the given fraction into a decimal form:

1) Since numerator is less than denominator, the integer component of the decimal number is zero:

$\frac{1}{15} = 0.xx$

2) We multiply the numerator by 10 and find the tenth digit:

$\frac{10}{15} = 0$

Then,

$\frac{1}{15} = 0.0xx$

3) We multiply the fraction in 2) by 10 and find the hundredth digit:

$\frac{100}{15} = 6$

Then,

$\frac{1}{15} = 0.66x$

And the remainder is:

$r = 100-15\times 6$

$r = 10$

4) We multiply the remainder by 10 and divide this result by the denominator to determine the thousandth digit:

$\frac{100}{15} = 6$

Then,

$\frac{1}{15} = 0.666$

This question asks us to write a decimal correct to 2 decimal places, which has the characteristic that is infinite periodical decimal. Then, the result correct to 2 decimal places is:

$\frac{1}{15} = 0.\overline{66}$

3 0

2 years ago

Please help me!! If you need a close up please don’t hesitate to ask!

aleksandrvk [35]

What’s the question?

7 0

3 years ago

What can be equal to 19

BartSMP [9]

19 can be equal to 19 and it should turn out to be as a whole number which is 1

7 0

3 years ago

Can someone pls help me??

frutty [35]

The second part would be $700. I'm not sure how I would solve the first part. You should click the hint button.<span />

8 0

3 years ago

Read 2 more answers

Instructions: Find the lengths of the other two sides of the isosceles right triangle below.

Alexandra [31]

Given:

The ratio of 45-45-90 triangle is $x:x:x\sqrt{2}$ .

The hypotenuse of the given isosceles right triangle is $7\sqrt{2}$ .

To find:

The lengths of the other two sides of the given isosceles right triangle.

Solution:

Let $l$ be the lengths of the other two sides of the given isosceles right triangle.

From the given information if is clear that he ratio of equal side and hypotenuse is $x:x\sqrt{2}$ . So,

$\dfrac{x}{x\sqrt{2}}=\dfrac{l}{7\sqrt{2}}$

$\dfrac{1}{\sqrt{2}}=\dfrac{l}{7\sqrt{2}}$

$\dfrac{7\sqrt{2}}{\sqrt{2}}=l$

$7=l$

Therefore, the lengths of the other two sides of the given isosceles right triangle are 7 units.

6 0

3 years ago