This information is not enough to tell which of the traits-blood group A or O is dominant.
It is known that blood groups A and B are codominant, which means both will express if found together in a heterozygote. However, blood group O is recessive. But from this information, you can conclude that blood group O is dominant. Why is that so?
Let's imagine that father's genotype is AA and mothers' genotype OO and cross them:
Parents: AA x OO
Offspring: AO AO AO AO
Since we have information that daughter has blood group O, we can conclude that O is dominant over A and mask it. This is not true! In this case, the daughter will have blood group A.
Mother's genotype surely is OO (because O allele is recessive, so to express a recessive trait both alleles must be recessive). But, the father cannot be AA, because it must give O allele to the daughter so she can have genotype OO and blood group O. So, the father's genotype is AO. Let's take a look at that crossing:
Parents: AO x OO
Offspring: AO AO OO OO
Thus, in this case, daughter can have genotype OO and blood group O.
You know that there is a difference between plant cells and animals cells. The plant cells have a cytoplasm while the animal cells do not. Therefore the answer must be C.
Answer:
The correct answer is "reduced initiation of translation".
Explanation:
The ribosome-binding site (RBS) is the sequence of DNA responsible for the recruitment of a ribosome, which results in the initiation of protein translation. A mutation that specifically occurs in a bacterial RBS may result in a reduced initiation of translation. A mutated RBS would likely fail to recruit the ribosome, which will affect the level of initiation of translation.
Baryonic dark matter may occur in non-luminous gas or in Massive Astrophysical Compact Halo Objects, and stars. So therefore it’s D.
A. Twelve cells with 16 chromosomes each
