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alexandr1967 [171]
3 years ago
11

The life of automobile voltage regulators has an exponential distribution with a mean life of six years. You purchase an automob

ile that is six years old, with a working voltage regulator and plan to own it for six years. a) What is the probability that the voltage regulator fails during your ownership
Mathematics
1 answer:
jeyben [28]3 years ago
5 0
Um I need help on this question too!!:( hshshshshanja
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Bob puts $500 into an account that pays 5% interestc ompounded anually. What is the balance after 5 years?
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Answer:

b

Step-by-step explanation:

7 0
3 years ago
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A boiler has five identical relief valves. The probability that any particular valve will open on demand is 0.95. Assuming indep
Gre4nikov [31]

Answer:

a) There is a 99.99997% probability that at least one valve opens.

b) There is a 22.62% probability that at least one valve fails to open.

Step-by-step explanation:

For each valve, there are only two possible outcomes. Either it open, or it does not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.95, n = 5

(a) What is the probability that at least one valve opens?

Either no valves open, or at least one opens. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1)

So

P(X \geq 1) = 1 - P(X = 0)

P(X = 0) = C_{5,0}.(0.95)^{0}.(0.05)^{5} = 0.0000003

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000003 = 0.9999997

There is a 99.99997% probability that at least one valve opens.

(b) What is the probability that at least one valve fails to open?

Either all valves open, or at least one does not open. The sum of the probabilities of these events is decimal 1. So

P(X = 5) + P(X \leq 4) = 1

We want P(X \leq 4)

So

P(X \leq 4) = 1 - P(X = 5)

P(X = 5) = C_{5,5}.(0.95)^{5}.(0.05)^{0} = 0.7738

P(X \leq 4) = 1 - P(X = 5) = 1 - 0.7738 = 0.2262

There is a 22.62% probability that at least one valve fails to open.

5 0
3 years ago
Buddy and his team have been asked by NASA to make a space shuttle cake (a scale model shaped like the one to the left) for a fu
Murrr4er [49]

Answer:

Ivette is wrong and by a lot. The spaceship should be 23.59 feet high

Step-by-step explanation:

The relationship between the spaceship's height and width = 184 feet : 78 feet ≈ 92 : 39 ≈ 9.2 : 3.9. This means that for every 3.9 feet wide, the cake should be 9.2 feet high.

In this case, the spaceship is 10 feet wide, so it should be (10 / 3.9) x 9.2 =  23.59 feet high.

When you make scale drawings or scale cakes, you must keep the same proportions as the original model.

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Find the perimeter of the following figure<br> plsplspls
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I think ts 58cm

please leave brainliest

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3 years ago
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