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krok68 [10]
3 years ago
11

Find the sum of the first 20 terms of the arithmetic sequence 4, 10, 16, 22....

Mathematics
1 answer:
hammer [34]3 years ago
3 0

n = 20

d = 6

a = 4

L = a + (n - 1)*d

L = 4 + (20 - 1)*6

L = 4 + 19*6

L = 118

Sum = (a + L)*n/2

Sum = (4 + 118) * 20/2

Sum = 122 * 10

Sum = 1220

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How to solve 2x(x+3)=2x^2+15
Travka [436]

Answer: x = 5/2 = 2.5

Step-by-step explanation:

<u>Given expression</u>

2x (x + 3) = 2x² + 15

<u>Expand parentheses and apply the distributive property</u>

2x · x + 2x · 3 = 2x² + 15

2x² + 6x = 2x² + 15

<u>Subtract 2x² on both sides</u>

2x² + 6x - 2x² = 2x² + 15 - 2x²

6x = 15

<u>Divide 6 on both sides</u>

6x / 6 = 15 / 6

x = 15/6

\boxed{x=\frac{5}{2} }

Hope this helps!! :)

Please let me know if you have any questions

5 0
3 years ago
Read 2 more answers
X + 24 + 4 + 63 = 180
Helen [10]

Answer:

x=89

Step-by-step explanation:

180-91=89

4 0
3 years ago
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Solve.
Eva8 [605]

2x^2+x-1=2\ \ \ |-2\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\ \ |-3\\2x=-3\ \ \ |:2\\x=-\frac{3}{2}\\\\x-1=0\ \ \ |+1\\x=1

Answer: C 1, -3/2

4 0
3 years ago
A customer desires to mix her own concrete. The clerk knows that the ratio of cement to sand to gravel is 1:3:4. If the customer
Aleks [24]

Answer:

The quantity of cement use is 125 pounds

The quantity of sand use is 375 pounds

The quantity of gravel use is 500 pounds

Step-by-step explanation:

Given as :

The ratio of cement to sand to gravel = 1 : 3 : 4

The total quantity of dry mix required = 1000 pounds

Let The quantity of cement required = 1 × x pounds

The quantity of sand required = 3 × x pounds

The quantity of gravel required = 4 × x pounds

So, According to question

The total quantity of dry mix required = The quantity of cement required + The quantity of sand required + The quantity of gravel required

Or, x + 3 x + 4 x = 1000 pounds

Or, 8 x = 1000 pounds

∴  x = \frac{1000}{8}

I.e x = 125

So , The quantity of cement required = 1 × 125 pounds = 125 pounds

The quantity of sand required = 3 × 125 pounds = 375 pounds

The quantity of gravel required = 4 × 125 pounds = 500 pounds

Hence The quantity of cement use is 125 pounds

The quantity of sand use is 375 pounds

The quantity of gravel use is 500 pounds

Answer

8 0
3 years ago
Which math operation is used to execute the distributive property?
pashok25 [27]

Answer: d , division . i think

4 0
3 years ago
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