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krok68 [10]
3 years ago
11

Find the sum of the first 20 terms of the arithmetic sequence 4, 10, 16, 22....

Mathematics
1 answer:
hammer [34]3 years ago
3 0

n = 20

d = 6

a = 4

L = a + (n - 1)*d

L = 4 + (20 - 1)*6

L = 4 + 19*6

L = 118

Sum = (a + L)*n/2

Sum = (4 + 118) * 20/2

Sum = 122 * 10

Sum = 1220

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48 cups

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Hello I’m trying to solve this problem I just don’t know how to do it.
Katyanochek1 [597]

Step-by-step explanation:

To evaluate the proposed, the comprehension of linear data is required,

Slope: The rise/run or the accumulative unit distance between two differentiated points on a linear.

X-intercept: The peculiar point in which the observed linear data intersects the x-axis.

Y-intercept: The peculiar point in which the observed linear data intersects the y-axis.

1. To solve the following systems, first convert the Slope-Intercept formatting to Standard (General) form:

y = -5/3x + 3

3(Y = -5/3x + 3) Product by the denominator to eliminate the fraction.

3y = -5x + 9. Add 5x to the other expression as in standard form, the slope must be positive.

5x + 3y = 9 <== Standard (General) Form.

Y = 1/3x - 3

3(y = 1/3x - 3). Product by the denominator to eliminate the fraction.

3y = x - 9. Subtract by x to place the slope within the other expression of the equation.

-1(-x + 3y = -9). Now, product by -1 to contribute to a positive slope.

X - 3y = 9 <=== Standard (General) Form.

2. To solve for the x and y values, utilize the system of substitution:

1(5x + 3y = 9)Multiply equations by opposite slope to the other, and a positive to other.

-5(X - 3y = 9)

Evaluate,

+ 5x + 3y = 9. Now, add the systems.

-5x + 15y = -45

——————————

18y = -36

Y = -2

Thus, now that y is equated to -2, substitute that to either equation.

X - 3y = 9

X - 3(-2) = 9

X + 6 = 9

X = 3

Thus, x = 3, y = -2. This is their intersection point.

To plot these lines on the graph, execute the following,

Y = -5/3 x + 3

Start with the y-intercept. Draw a point on number 3 on the y-axis (vertical).

Starting with that point, go down 5 units, right 3 units.

* Remember, if there is a negative rise, go down. Positive, go up. If there is a negative run, go left. Positive, go right.

* Keep going 5 units down, right 3 units, until the graph allows.

2. Y = 1/3 x - 3

Similarly, conduct the same steps:

Starting with the y-intercept, draw a point on -3 on the vertical, or y-axis.

Beginning on that point, go up 1 unit, right 3 units.

Keep going up 1 units and 3 units right until the graph permits.

*I hope this helps.

3 0
3 years ago
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