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stepan [7]
2 years ago
5

Jason can make 7 origami cranes in 10 minutes. How many minutes will it take to make 1505 origami cranes

Mathematics
2 answers:
Angelina_Jolie [31]2 years ago
8 0

Answer:

The unit rate = 7/10 cranes per minute

Step-by-step explanation:

So, the number of minutes would it would take Kenny to fold 1505 cranes is  

10/7 x 1505 = 2150 minutes

2150/60 = 35 5/6 hours

o-na [289]2 years ago
3 0

Answer:

2150 minutes

Step-by-step explanation:

The unit rate = 7/10 cranes per minute

So the number of minutes it would take Jason to make 1505 cranes is:

10/7 x 1505 = 2150 minutes.

Another way:

1505 cranes / 7 cranes = 215

215 x 10 minutes = 2150

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The ratio is boys to girls is 3:5. If there are 24 boys how many girls are in the class
RoseWind [281]
If the ratio is 3:5, then for every 3 boys there are 5 girls, so you multiply 3 and 5 by 24 and you get your answer.
4 0
3 years ago
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scoundrel [369]
The answer is 1 i did this before and hope this helps
5 0
2 years ago
It costs more to produce defective items - since they must be scrapped or reworked - than it does to produce non-defective items
ale4655 [162]

Answer: a) 1082, b) wider.

Step-by-step explanation:

Since we have given that

Margin of error = 0.1 millimeter  = E

Standard deviation = 2 mm = σ

Critical value would be

z_{\frac{\alpha}{2}}=z_{0.05}=1.645

a) Sample size would be

n=(\dfrac{z_{\frac{\alpha }{2}}\times \sigma}{E})^2\\\\n=(\dfrac{1.645\times 2}{1})^2\\\\n=1082.41\\\\n=1082

b) Sample size, n = 100

So, the margin of error would be

E=z_{\frac{\alpha }{2}}\times \dfrac{\sigma}{\sqrt{n}}\\\\E=1.645\times \dfrac{2}{\sqrt{100}}\\\\E=1.645\times \dfrac{2}{10}\\\\E=0.329

Since the margin of error in b part is more than a part, as we know that the higher the margin of error, the wider the confidence interval.

So, it would have wider confidence interval.

Hence, a) 1082, b) wider.

4 0
3 years ago
Chicken tenders or chicken nuggets
antiseptic1488 [7]

Answer:

i dont know which one to choose but chicken tenders

6 0
2 years ago
Helpppp asapppppp....
-BARSIC- [3]

Answer:

C.

Step-by-step explanation:

So, here's what you need to remember:

If we have a function <em>f(x)</em> and a factor <em>k</em>:

<em>k(f(x)) </em>will be a vertical stretch if k is greater than 1, and a vertical compression if k is greater than zero but less than 1.

<em>f(kx) </em>will be a horizontal compression if k is greater than 1, and a horizontal stretch if k is greater than zero but less than 1.

We are multiplying 0.5 to the function. In other words: 0.5f(x).

This is outside the function, so it's vertical.

0.5 is less than 1, so this would be a vertical compression

6 0
3 years ago
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