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3 years ago

Of the possible outcomes in the sample space, how many times does the event of rolling a multiple of two occur?

Mathematics

1 answer:

Alina [70]3 years ago

6 0

Answer:

dont know you know

Step-by-step explanation:

maybe try ask some one else i dont know

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What is 2 x 9 x 18 x 28 x 46 x 58, its a hard question

Yuliya22 [10]

2x9 is 18x18 is 324 x28 is 9072 x 46 is 417,312 so the x 58 the answer is 24,204,096

8 0

3 years ago

Read 2 more answers

4/6 written as a ratio is <br>

earnstyle [38]

Answer:

4:6

Step-by-step explanation:

Ratios and fractions can be written interchangably

6 0

3 years ago

Read 2 more answers

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

4 years ago

Which equation results from adding the equations in this system?

MArishka [77]

Answer:

8y = -6

Step-by-step explanation:

x + 6y -x +2y = 9 +(-15) ➡ 8y = -6

5 0

3 years ago

The length of a rectangular floor is 2 feet more than its width. The area of the floor is 168 square feet. Kim wants to use a ru

ioda

Let width of the floor be x feet, them area is
x(x+2) = 168
x^2 + 2x - 168 = 0
(x - 12)(x + 14) - 0
so x = 12
the floor is 12 ft by 10 ft

the width of the rug should be 10 - 2(2) = 6 feet

4 0

4 years ago