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sladkih [1.3K]
3 years ago
5

In a certain triangle, the measure of the largest angle is 20 degrees more than twice the measure of the smallest angle. Five ti

mes the measure of the smallest angle equals the sum of the measures of the other two angles. Find the measures of the three angles.
Mathematics
1 answer:
romanna [79]3 years ago
3 0
Let the medium angle be B degrees the small angle be A degrees the large angle be C degrees Then C = 2 B + 20 ..................X 5 B = A + C ..................Y Sum of all angles A + B + C = 180 .............Z Applying Y in Z 5 B + B = 180 6 B = 180 B = 30 From X C = 2 x 30 + 20 = 60 + 20 = 80 From Y 5 x 30 = A + 80 150 = A + 80 150 - 80 = A = 70 Hence medium angle B = 30 degrees the small angle A = 70 degrees the large angle C = 80 degrees
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Find the equation of a line passing through (-4,-3) and perpendicular to<br> 3 x + 2 y = 14.
Reil [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

3x+2y=14\implies 2y=-3x+14\implies y=\cfrac{-3x+14}{2}\implies y = \cfrac{-3x}{2}+\cfrac{14}{2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{3}{2}}x+7\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so therefore

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-3}{2}} ~\hfill \stackrel{reciprocal}{\cfrac{2}{-3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{2}{-3}\implies \cfrac{2}{3}}}

so we're really looking for the equation of a line whose slope is 2/3 and passes through (-4 , -3)

(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{2}{3}}(x-\stackrel{x_1}{(-4)}) \implies y+3=\cfrac{2}{3}(x+4) \\\\\\ y+3=\cfrac{2}{3}x+\cfrac{8}{3}\implies y=\cfrac{2}{3}x+\cfrac{8}{3}-3\implies y=\cfrac{2}{3}x-\cfrac{1}{3}

3 0
2 years ago
A person invest 7900 in an account growing at a rate allowing the money to double every 8 years. How much money would be in the
Aleonysh [2.5K]

Answer:

There will be $7,900.

Step-by-step explanation:

Seeing as it will double every EIGHT years, and 5 is less than eight, the amount will stay the same.

4 0
3 years ago
Mrs. Johnson is renting a car for vacation and plans to drive a total of 800 Miles. A rental car company charges $153 for the we
ch4aika [34]
No, she cannot afford the car. 
The total would be $176, and she only has $160.

Hope this helps!!
~Kiwi
6 0
3 years ago
Read 2 more answers
What is the approximate circumference of a circle with a radius of 30 inches? Use π ≈ 3.14.
Marina CMI [18]
The circumference<span> of a circle is the distance around the circle. </span>The circumference of a circle is calculated by the expression:

Circumference = 2πr

Circumference = 2π(30 inches)
Circumference = <span>94.2 inches
</span>
Therefore, the correct answer from the choices listed above is option C. Hope this answers the question.
3 0
3 years ago
The change in water level of a lake is modeled by a polynomial function, W(x). Describe how to find the x-intercepts of W(x) and
Agata [3.3K]
<span>First. <u>Finding the x-intercepts of </u>W(x)
</span><span>
Let W(x) be the change in water level. So to find the x-intercepts of this function we can use The Rational Zero Test that states:

To find the zeros of the polynomial:

f(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+...+a_{2}x^{2}+a_{1}x+a_{0}

We use the Trial-and-Error Method which states that a factor of the constant term:

a_{0}

can be a zero of a polynomial (the x-intercepts).

So let's use an example: Suppose you have the following polynomial:

W(x)=x^{4}-x^{3}-7x^{2}+x+6

where the constant term is a_{0}=6. The possible zeros are the factors of this term, that is:

1, -1, 2, -2, 3, -3, 6 \ and \ -6.

Thus:

</span>W(1)=0 \\ W(-1)=0 \\ W(2)=-12 \\ W(-2)=0 \\ W(3)=0 \\ W(-3)=48 \\ W(6)=840 \\ W(-6)=1260<span>

From the foregoing, we can affirm that 1, -1, -2 \ and \ 3 are zeros of the polynomial.

</span>Second. <u>Construction a rough graph of</u> W(x)

Given that this is a polynomial, then the function is continuous. To graph it we set the roots on the coordinate system. We take the interval:

[-2,-1]

and compute W(c) where c is a real number between -2 and -1. If W(c)>0, the curve start rising, if not, the curve start falling. For instance:

If \ c=-\frac{3}{2} \\ \\ then \ w(-\frac{3}{2})=-2.81

Therefore the curve start falling and it goes up and down until x=3 and from this point it rises without a bound as shown in the figure below


7 0
4 years ago
Read 2 more answers
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