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SOVA2 [1]
2 years ago
15

Which exponential function is represented by the graph

Mathematics
1 answer:
tamaranim1 [39]2 years ago
5 0

Answer:

the answer is "B" the second one...

(1/2)(2)^x

at

0 = (1/2)(1) = 1/2

2= (1/2)(4) = 2

Step-by-step explanation:

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In Illinois, 10 % of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been ar
docker41 [41]

Answer:

a) P(X=5) = 0.065

b) P(X≥1) = 0.928

c) The mean number of repeat offenders is 3.

d) The standard deviation of the number of repeat offenders is 2.

Step-by-step explanation:

n = 25

p = 10% = 0.10

q = 1-p

  = 1-0.1

q=0.9

a) Find P(X =5)

Using the binomial distribution formula:

P(X = x) = ⁿCˣ pˣ qⁿ⁻ˣ

where p = probability of success

           q = probability of failure

           n = total number of trials

           x = no. of successful trials

P(X=5) = ²⁵C₅ (0.1)⁵ (0.9)²⁵⁻⁵

           = 0.0645 ≅ 0.065

P(X=5) = 0.065

b) We need to find the probability that at least one person is a repeat offender which means at most there can be 25 repeat offenders hence, we need to compute the probability for all values ranging from 1 to 25. The easy way to solve this problem is to find out the probability of less than one repeat offender and then subtract the value from the total probability (i.e. 1).

   P(X≥1) = 1 - P(X<1)

              = 1 - P(X =0)

              = 1 - ²⁵C₀ (0.1)⁰ (0.9)²⁵⁻⁰

               = 1 - 0.072

   P(X≥1) = 0.928

c) The mean of the binomial distribution is:

         μ = np

So, the mean number of repeat offenders can be computed as:

μ = (25)(0.10)

μ = 2.5 ≅ 3

The mean number of repeat offenders is 3.

d) The standard deviation of the binomial distribution is:

   σ = √npq

So, the standard deviation of the number of repeat offenders can be computed as:

σ = √(25)(0.1)(0.9)

   = √2.25

σ = 1.5 ≅ 2

The standard deviation of the number of repeat offenders is 2.

7 0
2 years ago
Let f(x) = 4x + 2 and g(x) = 2x2-4. Find the formula for the composition function gf.​
Finger [1]
G(f(x))=? g(x)=2x^2-4? hope this is what you mean
g(f(x))=2(4x+2)^2-4
g(f(x))=2(16x^2+16x+4)-4
g(f(x))=32x^2+32x+8-4
g(f(x))=32x^2+32x+4
4 0
3 years ago
Draw a triangle that has no right angles
IRINA_888 [86]
Here's another one.
See the attached picture.

5 0
3 years ago
Read 2 more answers
What is the midpoint of 0 1000
ruslelena [56]
I think it might be 500

hope this helped =3
5 0
2 years ago
Read 2 more answers
Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

Second=16a^{2}

Third=25a^{2}

Fourth=24a^{2}

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

7 0
3 years ago
Read 2 more answers
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