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Margaret [11]
3 years ago
11

Write 4.399 as a ratio of two integers. Enter your answer as a reduced improper fraction.

Mathematics
1 answer:
Dahasolnce [82]3 years ago
4 0

Answer:

Rewrite the decimal number as a fraction with 1 in the denominator

4.399=4.3991

Multiply to remove 3 decimal places. Here, you multiply top and bottom by 103 = 1000Rewrite the decimal number as a fraction with 1 in the denominator

4.399=4.3991

Multiply to remove 3 decimal places. Here, you multiply top and bottom by 103 = 10004.3991×10001000=43991000

Simplify the improper fraction,

=43991000

In conclusion,

4.399=43991000

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Sav [38]

Answer:

B AND B Because they are the only awnsers that make grammatical sense.

6 0
2 years ago
The level of nitrogen oxides (NOX) in a exhaust of cars of a particular model varies normally with mean 0.25 grams per miles and
antoniya [11.8K]

Answer:

a) 15.87% probability that a single car of this model fails to meet the NOX requirement.

b) 2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

Step-by-step explanation:

We use the normal probability distribution and the central limit theorem to solve this question.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 0.25, \sigma = 0.05

a. What is the probability that a single car of this model fails to meet the NOX requirement?

Emissions higher than 0.3, which is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.3 - 0.25}{0.05}

Z = 1

Z = 1 has a pvalue of 0.8417.

1 - 0.8413 = 0.1587.

15.87% probability that a single car of this model fails to meet the NOX requirement.

b. A company has 4 cars of this model in its fleet. What is the probability that the average NOX level of these cars are above 0.3 g/mi limit?

Now we have n = 4, s = \frac{0.05}{\sqrt{4}} = 0.025

The probability is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.3 - 0.25}{0.025}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

4 0
3 years ago
Sarah had 25 candies. Sarah gave 25 of the candies to her sister. Of the amount left, she gave 2/3 to her friend. How many candi
RoseWind [281]

Answer:

She has 5 candles left.

Step-by-step explanation:

Total of candy Sarah has = 25candies

If Sarah gave 2/5 of the candies to her sister, the total amount she gave her sister will be 2/5 of 25

2/5 of 25 = 10

The remaining candy left will be 25-10 which is 15.

If she gave 2/3 of the amount left to her friend, the amount she gave her friend will be 2/3×15 = 10candies.

5 0
3 years ago
What is the equation of a line that is perpendicular to 2x+3y=9 and passes through the point (8,5)
pochemuha
For
ax+by=c
slope=-a/b

perpendiculare lines have slopes that multiply to -1

so

2x+3y=9
slope=-2/3
-2/3 times what=-1
what=3/2


point slope form
the equation of a line that passes through the point (x1,y1) and the slope is m is
y-y1=m(x-x1)
slope=3/2
point i (8,5)

equation is
y-5=3/2(x-8)
converted to standard form
2y-10=3x-24
-3x+2y=-14
3x-2y=14
7 0
3 years ago
Read 2 more answers
4. There are 8 students on the minibus. Five of the students are boys. What fraction of the students are boys?
Montano1993 [528]
<span>fraction of the students are boys = 5/8

hope it helps</span>
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3 years ago
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