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Murrr4er [49]
3 years ago
9

2- b/3 = -5/2...................

Mathematics
2 answers:
Sliva [168]3 years ago
7 0

Answer:

b = 7.5

b=7\frac{1}{2}

b=\frac{15}{2}

Step-by-step explanation:

\frac{-b}{3}= \frac{-5}{2}

- b × 2 = - 5 × 3

- 2b = - 15

- 2b ÷ - 2 = - 15 ÷ - 2

b = 7.5

Phantasy [73]3 years ago
3 0

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

b=\frac{27}{2}

»»————- ★ ————-««  

Here’s why:

⸻⸻⸻⸻

\boxed{\text{Calculating The Answer...}}\\\\2-\frac{b}{3}=-\frac{5}{2}\\--------------\\\rightarrow 2 - 2 -\frac{b}{3}=-\frac{5}{2}-2\\\\\rightarrow-\frac{b}{3}=-\frac{9}{2}\\\\\rightarrow (-\frac{b}{3})3=(-\frac{9}{2})3\\\\\rightarrow -b = -\frac{27}{2}\\\\\rightarrow \frac{-b = -\frac{27}{2}}{-1}\\\\\rightarrow \boxed{b=\frac{27}{2}}\text{ or } \boxed{b=13.5}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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We have f'(-2,y)>0 for -2 and f'(-2,y) for 2, which indicates a local maximum at y=2 and minima at the endpoints of this boundary. So

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f(x,x)=9x+1\implies f'(x,x)=9>0

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\begin{cases}f(-2,-2)=-17\\f(2,2)=19\end{cases}

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f(x,3)=x^3-3x+10\implies f'(x,3)=3x^2-3=0\implies x=\pm1

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