Just divide -6x+10 by -2 and take out what's common.
-6x divided by -2 would be
3x.
10 divided by -2 would be
-5.
So the answer is
-2(3x-5).
Answer:
A) T'(-3, 6) and V'(0, 3)
Step-by-step explanation:
In the picture attached, triangle TVW is shown.
Transforming points T and V according to the rule (x,y) -> (3/4x, 3/4y), we get:
T(-4, 8) -> (-4*3/4, 8*3/4) -> (-3, 6) which corresponds to T'
V(0, 4) -> (0*3/4, 4*3/4) -> (0, 3) which corresponds to V'
Answer:
good now that i get free points!
Step-by-step explanation:
Answer:
4073.76
Step-by-step explanation:
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
