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Ad libitum [116K]
3 years ago
12

5 1/10-1 7/10=A.3 3/5B.6 4/5C.3 2/5D. 3 3/10​

Mathematics
1 answer:
Alenkasestr [34]3 years ago
6 0
The answer is C

You're welcome
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Multiply the trinomials.
lora16 [44]

Answer:

b

Step-by-step explanation:

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3 years ago
the logarmithmic functions, f(x)=logx and g(x), are shown on the graph. what is the equation that represents g(x)? explain.​
mestny [16]

Answer:

g(x) = log(x+1) + 4

Step-by-step explanation:

If a curve has been translated (shifted or slid) you can add to or subtract from the x to show horizontal (left or right) shifts and add or subtract a number tacked onto the end of the equation to cause the vertical shift (up or down).

The curve for g(x) is shifted left 1 unit. So change the x to x+1. Left and right shifts are a little backwards from what you might think. But left shift is a +1.

Vertical shifts adjust the way you would think they should. UP shift 4 units is a +4 on the end of the equation. See image.

6 0
2 years ago
3 Meg found another treasure between -14 feet and 1 -22 feet. Where was that treasure?​
IceJOKER [234]

Answer:

- 18 feet

Step-by-step explanation:

3 0
3 years ago
a garden is in the shape of a rectangle 35 feet long and 29 feet wide. if fencing cost $7 a foot, what will it cost to plate fen
miskamm [114]
It would cost $896 to plate fencing around the garden
4 0
3 years ago
Let n be a natural number. Show that 3 | n3 −n
Vladimir [108]
Let n=1. Then n^3-n=1^3-1=0. By convention, every non-zero integer n divides 0, so 3\vert n^3-n.

Suppose this relation holds for n=k, i.e. 3\vert k^3-k. We then hope to show it must also hold for n=k+1.

You have

(k+1)^3-(k+1)=(k^3+3k^2+3k+1)-(k+1)=(k^3-k)+3(k^2+k)

We assumed that 3\vert k^3-k, and it's clear that 3\vert 3(k^2+k) because 3(k^2+k) is a multiple of 3. This means the remainder upon divides (k+1)^3-(k+1) must be 0, and therefore the relation holds for n=k+1. This proves the statement.
4 0
3 years ago
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