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2 years ago

What is the least common multiple of the two denominators?

Mathematics

1 answer:

rusak2 [61]2 years ago

8 0

Answer:

Step-by-step explanation:

32 × 1 = 32

8 × 4 = 32

Therefore, the LCM is 32

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Please help! What is the volume of the triangular pyramid?

vivado [14]

Answer:

30cm3

Step-by-step explanation:

Volume=Base area *height

Base area is a triangle=1/2 *base*height

1/2*3*4=6cm2

Height=5cm

Volume=6*5=30cm3

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3 years ago

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Which is the equation in standard form of the line that contains points C and D

bogdanovich [222]

B, 3x-2y=2 in standard form is y=-1-3/-2x.

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3 years ago

Please help me with this (5th grade math)

Tanya [424]

Answer:

kenis

Step-by-step explanation:

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3 years ago

PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!

Nookie1986 [14]

Answer:

$\large\boxed{y=\dfrac{1}{4}x^2-x-4}$

Step-by-step explanation:

The equation of a parabola in vertex form:

$y=a(x-h)^2+k$

(h, k) - vertex

The focus is

$\left(h,\ k+\dfrac{1}{4a}\right)$

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of a using $k+\dfrac{1}{4a}$

k = -5

$-5+\dfrac{1}{4a}=-4$ add 5 to both sides

$\dfrac{1}{4a}=1$ multiply both sides by 4

$4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4$

$\dfrac{1}{a}=4\to a=\dfrac{1}{4}$

Substitute

$a=\dfrac{1}{4},\ h=2,\ k=-5$

to the vertex form of an equation of a parabola:

$y=\dfrac{1}{4}(x-2)^2-5$

The standard form:

$y=ax^2+bx+c$

Convert using

$(a-b)^2=a^2-2ab+b^2$

$y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5$

use the distributive property: a(b+c)=ab+ac

$y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4$

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3 years ago

If roots of a quadratic equation are real and equal, then which of the

ycow [4]

Answer: where are the options??

Step-by-step explanation:

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3 years ago