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2 years ago

Help with problems 1 & 3

Mathematics

1 answer:

vlabodo [156]2 years ago

5 0

One side of the rectangle is x=2, the other side is 2x-5
Add up all the four sides: (x+2) +(x+2)+(2x-5)+(2x-5)=54
6x-6=54
x=10

#3: suppose the first integer is x, then the second one is x+2
x(x+2)=255
x^2 +2x -255 =0
factor the quadratic equation: (x+17)(x-15)=0
x=-17, which is impossible, or x=15
so the two positive integers are 15 and 17

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THIS IS MULTIPLE CHOICE!

Troyanec [42]

Answer:

there is a cluster from 1-4

there is a gap from 5-7

The spread is from 1-8

Step-by-step explanation:

These are all true if you look... there is a bunch from 1-4, there is none from 5-7, and all of them are within 1-8, but the highest amount isn't at 3.

7 0

2 years ago

As a fundraiser, the Music Boosters wrapped gifts at the mall one weekend. Out of the 100 gifts they wrapped, 3/10 were for wedd

dangina [55]

Answer: The fraction of the gifts were for birthdays = $\dfrac{33}{100}$ .

Step-by-step explanation:

Given: fraction of gifts for weddings = $\dfrac{3}{10}$

fraction of gifts for baby showers = $\dfrac{37}{100}$

Rest of the gifts = $1-\dfrac3{10}-\dfrac{37}{100}$

$=\dfrac{100-30-37}{100}\ \ \ [\text{Making like fractions}]\\\\=\dfrac{100-67}{100}\\\\=\dfrac{33}{100}$

Hence, the fraction of the gifts were for birthdays = $\dfrac{33}{100}$ .

4 0

2 years ago

If a+b=5 and a-b=4 then b^2-a^2 =

Anna007 [38]

Answer:

$a + b = 5 \\ a \: = 5 - b \\ a - b = 4 \\ 5 - b - b = 4 \\ 5 - 2b = 4 \\ 5 - 4 = 2b \\ 1 = 2b \\ \frac{1}{2} = \frac{2b}{2} \\0.5 = b \\ b = 0.5 \\ a = 5 - b \\ = 5 - 0.5 \\ = 4.5 \\ {a \: }^{2} - {b}^{2} = ( {4.5}^{2}) - ( {0.5}^{2} ) \\ = 20.25 - 0.25 \\ = 20 \\ {a}^{2} - {b}^{2} = 20$

Step-by-step explanation:

HOPE THAT THIS IS HELPFUL.

HAVE A GREAT DAY.

5 0

2 years ago

The quotient of 20 and four, multiplied by 10 as an expression

Genrish500 [490]

(20 / 4 )x 10

5 x 10

50

5 0

2 years ago

Log*subscript*(3x − 2) 4096 = 3<br><br> I got x= negative 6 is this correct??

Brut [27]

Remember

$log_a(b)=c$ translates to $a^c=b$
and
$log_a(b^c)=clog_a(b)$
so

4096=16^3
$log_{3x-2}(4096)=3$
$log_{3x-2}(16^3)=3$
$3log_{3x-2}(16)=3$
divide both sides by 3
$log_{3x-2}(16)=1$
translate
$(3x-2)^1=16$
3x-2=16
add 2 to both sides
3x=18
divide both sides by 3
x=6

8 0

3 years ago