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V125BC [204]
3 years ago
14

PLSSS HELP 5 GIVING POINTS PLUS BRAINLIEST

Mathematics
2 answers:
Finger [1]3 years ago
8 0

Answer:

the answer is B

Step-by-step explanation:

it makes the most sense

Debora [2.8K]3 years ago
8 0

Answer:

JsjsjsnsnsnsmsjsmznzmNMMMMmakakaKKKkzkzkzkzkzkzkjz kaKKKa

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Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st
Naily [24]

Answer:

\boxed{2^{\frac{802}{27}} \cdot 3^9}

Step-by-step explanation:

<u>I will try to give as many details as possible. </u>

First of all, I just would like to say:

\text{Use } \LaTeX !

Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! (*^U^)人(≧V≦*)/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

\left(\dfrac{1}{3^2}  \cdot \dfrac{1}{4^5}  \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3

Also,

\boxed{a^{0} = 1, a\neq 0 }

\left(\dfrac{1}{9}  \cdot \dfrac{1}{1024}  \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

Note

\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq  0}

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

Note

\boxed{\dfrac{1}{\dfrac{1}{a} }  = a}

9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)

Once

9216=2^{10}\cdot 3^2 \implies  9216^3=2^{30}\cdot 3^6

\boxed{(a \cdot b)^n=a^n \cdot b^n}

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27} $

We have

\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)

Also, once

\boxed{\dfrac{c^a}{c^b}=c^{a-b}}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27

As

30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27}  =\dfrac{802}{27}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3

2^{\frac{802}{27}} \cdot 3^9

4 0
3 years ago
Compare the rates to find which is the best value.
Nikolay [14]

Answer:

6 greeting cards for 23.40

7 0
3 years ago
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Who is your fave celebrity
andrew-mc [135]

Answer:

arianna grande

Step-by-step explanation:

8 0
3 years ago
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Need help! will award brainiest
coldgirl [10]

Answer:

\sf slope: \boxed{\bf \frac{1}{3} }

Explanation:

\sf slope :\dfrac{y_2-y_1}{x_2-x_1} =\dfrac{rise}{run} \  \ \  \  where  \ (x_1, \ y_1) ,(x_2, \ y_2)  \ are \ points

Find slope:

\rightarrow \sf \dfrac{x_2-x_1}{y_2-y_1}

<em>insert values</em>

\rightarrow \sf \dfrac{3-5}{-4-2}

<em>simplify</em>

\rightarrow \sf \dfrac{1}{3}

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2 years ago
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Alma and Blanca are playing a game where they roll a pair of fair six-sided dice and try to predict the outcomes. Blanca thinks
Eduardwww [97]
B because it is b enjoy
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3 years ago
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