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AlexFokin [52]
3 years ago
9

Can anyone help me out with this math problem?

Mathematics
1 answer:
inna [77]3 years ago
8 0
The slope is negative
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Need help! Will brainiest if right!
tangare [24]

Answer:

Y=3x+5

Step-by-step explanation:

If we take x = 1, according to the first function (the answer) y would be 8.

Other options:

—————

Formula 3:

Y= 2^x+5 == 7

Formula 4:

Y = x+8 == 9

True answer = 10.

——————

Ok, so the last one seems more accurate lets test the first and last one on two more numbers:

——————

X = 15

Formula 1:

50

Formula 4:

23

True answer = 60.

The first formula wins.

————————-

X= 10

Formula 1:

35

Formula 4:

18

True answer = 41

The first formula wins.

——————

So, we can see that the first formula is most accurate.

4 0
2 years ago
Please help!!! I don't understand how this works.
frosja888 [35]

Answer:

Step-by-step explanation:

64,000 x 6.2% divided by groups of 1.45 a

5 0
3 years ago
Read 2 more answers
Helpppppppp asap 89points
Lynna [10]

Answer:

the answer for the first is the second one

and the answer for the second is 9>6

Step-by-step explanation:

9 is greater than (>) six

and when plotted you can see that 9 is to the right of -6

hope i helped!

7 0
2 years ago
Read 2 more answers
Order the measurements from the least to the greatest. 2,720 mL , 24.91 L , 0.0268 kL
iren [92.7K]
2720ml=2.720L
0.0268kl=26.8L
24.91l
Therefore
2720ml , 24.91L, 0.0268kl
Is the correct order
8 0
3 years ago
Read 2 more answers
For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed wi
8090 [49]

Explanation:

Lets interpret Z with M trials. First we have M trials, each trial can be a success or not. The number of success is called N. Each trial that is a success becomes a trial, and if it is a success it becomes a success for Z. Thus, in order for a trial to be successful, it needs first to be successful for the random variable N (and it is with probability q), and given that, it should be a success among the N trials of the original definition of Z (with probability p).

This gives us that each trial has probability pq of being successful. Note that this probability is pq independently of the results of the other trials, because the results of the trials of both N and the original definition of Z are independent. This shows us that Z is the total amount of success within M independent trials of an experiment with pq probability of success in each one. Therefore, Z has Binomial distribution with parameters pq and M.

7 0
2 years ago
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