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AlexFokin [52]
3 years ago
9

Can anyone help me out with this math problem?

Mathematics
1 answer:
inna [77]3 years ago
8 0
The slope is negative
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Find the values of X and Y. Write your answers in simplest form.<br> X=__<br> Y=__
uranmaximum [27]
Hope this helps!
Anymore doubt, ask away

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3 years ago
The Rawlins family has travelled 600 km on their vacation. This has taken them 8 hours. If they continued at the same rate, how
spin [16.1K]

Answer:

B. 28 hours

Step-by-step explanation:

GIVEN :- <em>Time taken by family to travel 600 km is 8 hours</em>

CALCULATIONS :-

<em>To calculate the time to travel 2100 km, we need to calculate distance traveled in 1 hour</em>

<em>Distance traveled in 1 hour = 600 km ÷ 8</em>

<em>                                              = 75 km</em>

<em>Time required to travel 2100 km = 2100 ÷ 75</em>

<em>                                                         = </em><em>28 hours</em>

Therefore time required to travel 2100 km is 28 hours.


6 0
3 years ago
What prevent is modeled below
r-ruslan [8.4K]

Answer:

B 35%

Step-by-step explanation:

35/100 reduces to .35. To turn this into a percent, multiply it by 100 and add a percent sign. .35 * 100 = 35. 35%

3 0
4 years ago
Read 2 more answers
What answer to this question?
horrorfan [7]

Answer:

221

Step-by-step explanation:

13 x 17 = 221

4 0
3 years ago
A marketing firm is considering making up to three new hires. Given its specific needs, the management feels that there is a 50%
IRISSAK [1]

Answer:

a) 0.9

b) Mean = 1.58

Standard Deviation = 0.89

Step-by-step explanation:

We are given the following in the question:

A marketing firm is considering making up to three new hires.

Let X be the variable describing the number of hiring in the company.

Thus, x can take values 0,1 ,2 and 3.

P(x\geq 2) = 50\%= 0.5\\P(x = 0) = 10\% = 0.1\\P(x = 3) = 18\% = 0.18

a) P(firm will make at least one hire)

P(x\geq 2) = P(x=2) + P(x=3)\\0.5 = P(x=2) + 0.18\\ P(x=2) = 0.32

Also,

P(x= 0) +P(x= 1) + P(x= 2) + P(x= 3) = 1\\ 0.1 + P(x= 1) + 0.32 + 0.18 = 1\\ P(x= 1) = 1- (0.1+0.32+0.18) = 0.4

\text{P(firm will make at least one hire)}\\= P(x\geq 1)\\=P(x=1) + P(x=2) + P(x=3)\\ = 0.4 + 0.32 + 0.18 = 0.9

b) expected value and the standard deviation of the number of hires.

E(X) = \displaystyle\sum x_iP(x_i)\\=0(0.1) + 1(0.4) + 2(0.32)+3(0.18) = 1.58

E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89

7 0
3 years ago
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