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Elden [556K]
3 years ago
7

Some seeds contain fluffy parachute like structure why​

Mathematics
1 answer:
alekssr [168]3 years ago
7 0

lowkeyokfgfggfggeeeeeeeeeeeeeeeeeee

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Solve for d<br> –3d + 10 − 5d = –10 − 10d
deff fn [24]
Your answer would be -2
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Suddenly, the number of problems the mathletes have to solve increases by 60%! To keep on track, the mathletes try to go faster
sesenic [268]

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28%

Step-by-step explanation:

I did it and it was right

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Not sure on how to solve anymore.<br> A)43.92<br> B)41.45<br> C)68.87<br> D)33.1
Alenkasestr [34]
Sin (37°) = opposite side/Hypotenuse

sin (37°) =CV/55 →CV = 55.si  (37°)

CV = 55 x (0.601815)
CV= 33
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3 years ago
Parallel lines intersect at an angle of 90. A. True B. False
Lisa [10]
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8 0
3 years ago
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Need help simplifying this
diamong [38]

The simplified answer is \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}.

<u>Step-by-step explanation:</u>

$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term (\frac{3x+y}{3x+y}) and 2nd term by (\frac{z+2x}{z+2x})

= \frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= \frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}

Now, the denominators are same, you can subtract it.

= \frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

= \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

Thus the simplified solution is  \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

4 0
3 years ago
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